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Lelechka [254]
3 years ago
14

A 40 mph wind is blowing past your house and speeds up as it flows up and over the roof. If the elevation effects are negligible

, determine (a) the pressure at the point on the roof where the speed is 60 mph if the pressure in the free stream blowing toward your house is 14.7 psi. Would this effect tend to push the roof down against the house, or would it tend to lift the roof
Engineering
1 answer:
Finger [1]3 years ago
7 0

The pressure at the point on the roof where the speed is 60mph is 14.66 psi

<u>Explanation:</u>

The question follows Bernoulli's equation

P1 + 1/2 ρ V1² = P2 + 1/2 ρ V2²

V1 = 40 X 5280 / 3600 = 58.7 ft/s

V2 = 60 X 5280 / 3600 = 88 ft/s

P2 = P1 + 1/2 ( 0.00238 ) [(58.7)² - (88)²]

P2 - P1 = -5.12lb/ft²

The negative pressure created tends to lift the roof.

We know,

P1 = 14.7 psi = 2116.8 lb/ft²

P2 = 2116.8 - 5.12 lb/ft²

P2 = 2111.68 lb/ft²

P2 = 14.66 psi

Therefore, the pressure at the point on the roof where the speed is 60mph is 14.66 psi

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Explanation:

1.Mohamed Siddiqui appeals his convictions for fraud and false statements to a federal agency, and obstruction in connection with a federal investigation.   Siddiqui challenges the district court's admission into evidence of e-mail and foreign depositions.

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Consider casting a concrete driveway 40 feet long, 12 feet wide and 6 in. thick. The proportions of the mix by weight are given
Akimi4 [234]

Answer:

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Weight of sand = 18105.9 lb

Weight of gravel = 28203.55 lb

Weight of water = 5484 lb

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Length, L = 40 ft

Width,w = 12 ft

thickness,b= 6 inch, convert to ft = 6/12 = 0.5 ft

Specific gravity of sand = 2.60

Specific gravity of gravel = 2.70

The volume will be:

40 * 12 * 0.5 = 240 ft³

We need to find the dry volume of concrete.

Dry volume = wet volume * 1.54 (concrete)

Dry volume will be = 240 * 1.54 = 360ft³

Due to the 7% entarained air content, the required volume will be:

V = 360 * (1 - 0.07)

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At a ratio of 1:2:3 for cement, sand, and gravel respectively, we have:

Total of ratio = 1+2+3 = 6

Their respective volume will be =

Volume of cement = \frac{1}{6}*334.8 = 55.8 ft^3

Volume of sand = \frac{2}{6}*334.8 = 111.6 ft^3

Volume of gravel = \frac{3}{6}*334.8 = 167.4 ft^3

To find the pounds needed the driveway, we have:

Weight = volume *specific gravity * density of water

Specific gravity of cement = 3.15

Weight of cement =

55.8 * 3.15 * 62.4 = 10968 pounds

Weight of sand =

111.6 * 2.60 * 62.4 = 18105.9 lb

Weight of gravel =

167.4 * 2.7 * 62.4 = 28203.55 lb

Given water to cement ratio of 0.50

Weight of water = 0.5 of weight of cement

= 1/2 * 10968 = 5484 lb

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