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jek_recluse [69]
3 years ago
15

Match the measuring instrument with its description.

Engineering
1 answer:
BARSIC [14]3 years ago
3 0

Answer:

1. Clepsydra

2. Barometer

3. Chronometer

4. Se*tant

Explanation:

1. A clepsydra is a device that measures time by using a regulated fluid flow. It looks like a hour glass.

2. A barometer is a device that measures pressure. The level of liquid inside of its tubes changes with the atmospheric pressure change.

3. A chronometer is used to determine a position while knowing latitude, longitude, and altitude.

4. A se*tant has an arc of a circle and a movable arm pivoted at the center of the circle. It is used to view the horizon and also celestial bodies.

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Which of the following terms is defined as small bumps and slashes within a fluid power system?
-BARSIC- [3]

Answer:

friction

Explanation:

''.''

7 0
3 years ago
Read 2 more answers
Why are photopolymers essential for stereolithography?
Leokris [45]

Answer:

They essential for the formation of layers in a 3-D model.

Explanation:

Stereolithography is 3D printing process in which a 3D model can be created. In stereolithography technology, there is vat of the UV curable photopolymer which is placed below in lower compartment of machine.

<u>When the machine begins to construct 3D model by the scanning and the  building of one layer at one time. Each layer in the model is constructed with UV laser and as laser traces next layer of object material hardens on contact.  </u>

Once layer is complete, platform slips down to make room for next layer. This is how, a model is created.

5 0
3 years ago
You are performing a machining operation that approximates orthogonal cutting. Given that the chip thickness prior to chip forma
Mnenie [13.5K]

Answer:

A)

shear plane angle = 31.98°

shear strain = cot ( 31.98° ) + tan ( 31.98 - 10 )

B) shear strength = 7339.78

Explanation:

<u>a) Determine the shear plane angle and shear strain</u>

Given data :

Chip thickness before chip formation = 0.5 inches

Chip thickness after separation = 1.125 inches

rake angle ( ∝ ) = 10°  

<u>shear plane angle </u>: Tan ∅ = \frac{rcos\alpha }{1-sin\alpha }    ----- ( 1 )

r = chip thickness ratio = 0.5 / 1.125 = 0.4444

back to equation 1 : Tan ∅ = ( 0.444 ) * cos 10 / 1 - sin 10

Tan ∅ = 0.4444 * 0.9848 / 1 - 0.1736  = 0.5296

hence ∅ = tan^-1 ( 0.5296 ) = 31.98°

<u>shear strain</u> :  R = cot ∅ + tan ( ∅ - ∝ ) ---------- ( 1 )

R = cot ( 31.98° ) + tan ( 31.98 - 10 )

  <u>B) determine the shear strength of the material</u>

cutting force = 1559 N

thrust force = 1271 N

width of cut ( diameter ) = 3.0 mm

shear strength = c + σ.tan ∅

c = cohesion force  = 1271 * 3  = 3813

σ = normal stress  = F / A = 1559 / π/4 * ( 0.5 )^2 = 1559 / 0.1963 = 7941.94

hence : shear strength of material = 3813 + 7941.94 * 0.6244 = 7339.78

3 0
3 years ago
Silicon is the most widely used semiconductor material for integrated circuits. Which of the following are less common semicondu
Alenkasestr [34]

Answer:

c) gallium arsenide ,d) germanium

Explanation:

Silicon is the mostly used semiconductor material which used in integrated circuits,because it have some unique properties which make it so useful in electronics industries.

Silicon also can use as insulator as well as conductor .It is generally found in earth crust.

Gallium arsenide and germanium are material which have less used in integrated circuit.

5 0
3 years ago
D 4.37. Assuming the availability of diodes for which vD = 0.75 V at iD = 1mA, design a circuit that utilizes four diodes connec
gregori [183]

Answer:

R = 0.5825 k ohm

Explanation:

given data

vD = 0.75 V

iD = 1mA

resistor R = 15-V

solution

we get here first vD that is

vD = \frac{3.3}{4}  

vD = 0.825

so

iD = Ise × e^{\frac{vD}{nvT}}      

n = 1

so we can say

\frac{iD2}{iD1} = e^{\frac{vD2-vD1}{nvT}}  

so it will

iD2 = iD1 × e^{\frac{vD2-vD1}{nvT}}

put here value and we get

iD2 = 1 × e^{\frac{0.825-0.75}{25}}  

iD2 = 1 × e^{3}  

iD2 = 20.086 mA

so

R will be

R = \frac{15-3.3}{ID}  

R = 0.5825 k ohm

6 0
3 years ago
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