What safety precautions are needed when running a brine electrolysis plant

You finally earn your drivers license and are extremely excited to start driving! It is the middle of winter and all 4 tires on

anygoal [31]

Answer: Tires air condenses and when it condenses it takes up less room.

Explanation: Hope that helps!

5 0

3 years ago

In the titration between potassium iodate and the sodium thiosulfate solution, if the titration is not performed immediately aft

N76 [4]

Answer:

The calculated concentration of sodium thiosulphate solution will be less than the actual value.

Explanation:

When IO3^2- solution is added to KI solution, I2 gas is released ,then sulphuric acid is now added to facilitate reduction. In order to prevent the escape of iodine (I2) gas ,the solution must immediately be titrated with thiosulphate.

If the solution is not immediately titrated with thiosulphate, the concentration of iodine available in the system decreases. When this occurs, it will also cause a decrease in the amount of iodine available to react with thiosulphate thus decreasing the concentration of thiosulphate obtained from calculation

5 0

3 years ago

Ann and Carol each lift the timber with a force of 80 kg/m/s2. If they lift the timber a distance of 1.25 meters, how much work

Novosadov [1.4K]

Work is defined energy transferred from one to another.
The formula for work done is work done = force x distance

So in our problem, force is equal to 80 kg/ m / s^2 and distance is equal to 1.25 meters. So plugging in our values will give us:

work done = 80 kg/ m/ s^2 * 1.25 m
= 100.00 J is the answer.

4 0

3 years ago

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con

erik [133]

Explanation:

The given data is as follows.

Thickness (dx) = 0.87 m, thermal conductivity (k) = 13 W/m-K

Surface area (A) = 5 $m^{2}$ , $T_{1} = 14^{o}C$

$T_{2} = 93^{o}C$

According to Fourier's law,

Q = $-kA \frac{dT}{dx}$

Hence, putting the given values into the above formula as follows.

Q = $-kA \frac{dT}{dx}$

= $-13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}$

= 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

4 0

3 years ago

PCl3(g) + Cl2(g) ⇋ PCl5(g) Kc = 91.0 at 400 K. What is the [Cl2] at equilibrium if the initial concentrations were 0.24 M for PC

Dmitry_Shevchenko [17]

Answer:

[Cl₂] in equilibrium is 1.26 M

Explanation:

This is the equilibrium:

PCl₃(g) + Cl₂(g) ⇋ PCl₅(g)

Kc = 91

So let's analyse, all the process:

PCl₃(g) + Cl₂(g) ⇋ PCl₅(g)

Initially 0.24 M 1.50M 0.12 M

React x x x

Some amount of compound has reacted during the process.

In equilibrium we have

0.24 - x 1.50 - x 0.12 + x

As initially we have moles of product, in equilibrium we have to sum them.

Let's make the expression for Kc

Kc = [PCl₅] / [Cl₂] . [PCl₃]

91 = (0.12 + x) / (0.24 - x) ( 1.50 - x)

91 = (0.12 + x) / (0.36 - 0.24x - 1.5x + x²)

91 (0.36 - 0.24x - 1.5x + x²) = (0.12 + x)

32.76 - 158.34x + 91x² = 0.12 +x

32.64 - 159.34x + 91x² = 0

This a quadratic function:

a = 91; b= -159.34; c = 32.64

(-b +- √(b² - 4ac)) / 2a

Solution 1 = 1.5

Solution 2 = 0.23 (This is our value)

So [Cl₂] in equilibrium is 1.50 - 0.23 = 1.26 M

5 0

4 years ago