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EleoNora [17]
2 years ago
10

Calculate the momentum of a 32 kg eagle diving down to the water to catch a fish. During the dive, the eagle

Physics
1 answer:
I am Lyosha [343]2 years ago
4 0

The eagle momentum : 320 kg.m/s

<h3>Further explanation</h3>

Given

mass = 32 kg

d = 100 m

t = 10 s

Required

The momentum

Solution

The velocity of the eagle :

\tt v=\dfrac{d}{t}\\\\v=\dfrac{100}{10}=10~m/s

The momentum (P) :

\tt P=m\times v\\\\P=32\times 10\\\\P=320~kg.m/s

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on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker
DIA [1.3K]
<u>Momentum</u> 
- a vector quantity; has both magnitude and direction
- has the same direction as object's velocity
- can be represented by components x & y.

Find linebacker momentum given m₁ = 120kg, v₁ = 8.6 m/s north
P₁ = m₁v₁
P₁ = (120)(8.6)
[ P₁ = 1032 kg·m/s ] = y-component, linebacker momentum

Find halfback momentum given m₂ = 75kg, v₂ = 7.4 m/s east
P₂ = m₂v₂
P₂ = (75)(7.4)
[ P₂ = 555 kg·m/s ] = x-component, halfback momentum

Find total momentum using x and y components.
P = √(P₁)² + (P₂)²
P = √(1032)² + (555)²
[[ P = 1171.77 kg·m/s ]] = magnitude 

!! Finally, to find the magnitude of velocity, take the divide magnitude of momentum by the total mass of the players.
P = mv
P = (m₁ + m₂)v
1171.77 = (120 + 75)v      <em>[solve for v]</em>
<em />v = 1171.77/195
v = 6.0091 ≈ 6.0 m/s

If asked to find direction, take inverse tan of x and y components.
tanθ = (y/x)
θ = tan⁻¹(1032/555)
[ θ = 61.73° north of east. ]

The magnitude of the velocity at which the two players move together immediately after the collision is approximately 6.0 m/s.
6 0
3 years ago
Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​
Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ )}{9.8}}

d=35.35\ m

The range is 35.35 m

7 0
3 years ago
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JulijaS [17]
Total amount of energy would remain constant according to law of conservation of energy. i.e., 50 Joules

In short, Your Answer would be Option C) <span>50 Joules because as energy converts from one form to another, it cannot be created or destroyed during the conversion.
</span>
Hope this helps!

7 0
3 years ago
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Why is it dangerous to connect a battery to itself. what is the term used to describe that
Yuki888 [10]
In the circuit outside of the battery the electrons have to expend all of their energy on the internal resistance of the battery which causes heating
8 0
3 years ago
Please answer me!!! asappp​
Anastasy [175]

Answer:

omg this is hard

Explanation:

Yes it is lol

5 0
2 years ago
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