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3 years ago

10

Why should a tennis player "swing through" when hitting a tennis ball?

1 answer:

kondaur [170]3 years ago

7 0

If a tennis player does not swing through, meaning they stop swinging the moment they make contact with the ball, they would lose the majority of their power. <em>The momentum that they had built up during the swing is lost the moment they stop swinging</em>, meaning that the ball is hit with a low amount of power.

<em>If the tennis player swings through the whole time they hit the ball, then they keep their momentum as they hit the ball.</em> There is a much higher power level when swinging through than if you were to stop your swing when you hit the ball.

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You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,

lbvjy [14]

Answer:

The value is $T_c = 12 .1 ^oC$

Explanation:

From the question we are told that

The mass of the ice cube is $m_i = 7.50 *10^{-3} \ kg$

The temperature of the ice cube is $T_i = 0^o C$

The mass of the copper cube is $m_c = 0.540 \ kg$

The final temperature of both substance is $T_f = 0^oC$

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

$Q = m_c * c_c * [T_c - T_f ]$

The specific heat of copper is $c_c = 385J/kg \cdot ^oC$

Generally the heat gained by the ice cube is mathematically represented as

$Q_1 = m_i * L$

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So

$Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}$

=> $Q_1 = 2505 \ J$

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$2505 = 0.540 * 385 * [T_c - 0 ]$

=> $T_c = 12 .1 ^oC$

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