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3 years ago

Which are ways to improve the design of this experiment? Check all that apply.

2 answers:

6 0

-Reduce the sample size so the experiment can be done faster.-Increase the sample size from 6 cups to 12 cups of sand and water.-Use more legible handwriting when recording data.-Use more precise digital thermometers.<span>-Use more precise scales that measure to the hundredth of a gram.</span>

Sphinxa [80]3 years ago

3 0

Answer:

Use a video camera to record the height of each beanbag with greater accuracy.

Use a pressure sensor to record the force of the soda bottle more accurately.

Increase the number of trials for each experiment by a factor of three.

Explanation:

Just did this!

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A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60

Leto [7]

Answer:

The number of protons 6.19 more than electron.

Explanation:

Given that,

Charge $Q=+9.9\times10^{-6}\ C$

We know that,

formula of charge

$Q = nc$

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

$n = \dfrac{Q}{e}$

$n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}$

$n=6.1875\times10^{13}\ C$

According to statement of question

Divide the answer by $10^{13}$

$n=\dfrac{6.1875\times10^{13}}{10^{13}}$

$n=6.19\ C$

Hence, The number of protons 6.19 more than electron.

6 0

3 years ago

g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?

beks73 [17]

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

$F = \sqrt{F_x^2 + F_y^2}$

$F = \sqrt{5.69^2 + 8^2}$

$F = \sqrt{32.3761 + 64}$

$F = \sqrt{96.3761}$

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

4 0

2 years ago

Read 2 more answers

A 50-g chunk of 80 degrees C iron is dropped into a cavity in a very large block of ice at 0 degrees C. Show that 5.5 g of ice w

Alenkasestr [34]

Answer:

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

$Q = mc\Delta T$

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

$\Delta T =$ Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

$Q = mc\Delta T$

$Q = 50*0.11*(80-0)$

$Q = 440cal$

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

$Q_2 = mL = 80*m$

How Q_1=Q_2, so

$80m=440$

$m=\frac{440}{80}$

$m = 5.5g$

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

7 0

3 years ago

How do you measure the wavelength of a transverse wave?

DENIUS [597]

By looking at how wiggily the bar is lol

8 0

3 years ago

A pump is used to transport water to a higher reservoir. if the water temperature is 15ºc, determine the lowest pressure that ca

Reika [66]

Normally, the water pressure inside a pump is higher than the vapor pressure: in this case, at the interface between the liquid and the vapor, molecules from the liquid escapes into vapour form. Instead, when the pressure of the water becomes lower than the vapour pressure, molecules of vapour can go inside the water forming bubbles: this phenomenon is called cavitation.

So, cavitation occurs when the pressure of the water becomes lower than the vapour pressure. In our problem, vapour pressure at $15^{\circ}$ is 1.706 kPa. Therefore, the lowest pressure that can exist in the pump without cavitation, at this temperature, is exactly this value: 1.706 kPa.

7 0

3 years ago