Answer:
H2SO3 + 2CsOH —> Cs2SO3 + 2H2O
Explanation:
When sulfurous acid react with caesium hydroxide, caesium sulfite and water are formed according to the equation:
H2SO3 + CsOH —> Cs2SO3 + H2O
Next, we balanced the equation by putting 2 in front of CsOH and 2 in front of H2O i.e
H2SO3 + 2CsOH —> Cs2SO3 + 2H2O
Answer:
The unbalanced chemical equation: H₂O₂ → H₂O + O₂.
The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.
Explanation:
- Hydrogen peroxide is decomposed into oxygen and water, which is a slow reaction.
- It is can be catalyzed by using yeast.
The unbalanced chemical equation: H₂O₂ → H₂O + O₂.
The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.
1.0 mol of H₂O₂ is decomposed to 1.0 mol of H₂O and 0.5 mol of O₂.
Answer:

Explanation:
The molar mass is the mass of a substance in grams per mole.
To find it, add the mass of each element in the compound. These masses can be found on the Periodic Table.
The compound given is:

The compound has 1 Ca (calcium) and 2 Cl (chlorine).
Mass of Calcium
- The molar mass of calcium is 40.08 g/mol
- There is only one atom of Calcium in CaCl₂, so the number above is what we will use.
Mass of Chlorine
- The molar mass of chlorine is 35.45 g/mol
- There are two atoms of chlorine in CaCl₂, therefore we need to multiply the molar mass by 2.
- 35.45 * 2= 70.9 g/mol
Molar Mass of CaCl₂
- Now, to find the molar mass, add the molar mass of 1 calcium and 2 chlorine.
- 40.08 g/mol + 70.9 g/mol =110.98 g/mol
The molar mass of CaCl₂ is <u>110.98 grams per mole. </u>
Answer:
2.39 atm
Explanation:
- Use Gay-Lussac's law
- P2 = P1T2/T1
- Fill in with our values
- Hope this helped! Please let me know if you need further explanation.
(a) In this section, give your answers to three decimal places.
(i)
Calculate the mass of carbon present in 0.352 g of CO
2
.
Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g
of
A
.
(ii)
Calculate the mass of hydrogen present in 0.144 g of H
2
O.
Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g
of
A
.
(iii)
Use your answers to calculate the mass of oxygen present in 0.240 g of
A
Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g
of
A
(b)
Use your answers to
(a)
to calculate the empirical formula of
A
thank you
hope it helpsss