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USPshnik [31]
3 years ago
8

Why isn't carbon-14 dating accurate for estimating the age of materials older than 50,000 years?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
5 0
Carbon-14 is radioactive isotope of carbon.
Carbon is essential element of living cells. While the living cells are alive, the carbon contained in them are in equilibrium with the carbon in atmosphere. But, once the cell dies, the carbon-14 isotope undergoes radioactive decay. By measuring the carbon-14 in atmosphere to the carbon-14 in dead organism, we can calculate the time (or years) that organism have died.

However, carbon-14 dating technique is not accurate for estimating the age of materials older than 50,000 years old (above 40,000 years). This is because, 99% of carbon is carbon-12, 1% is carbon-13 and trace remaining is the carbon-14. This means, carbon-14 is found in very trace amount, in fact 1 part per trillion of carbon atoms present is carbon-14. The half of life of carbon-14 is 5,730 years. For dating the organism, we use the concept of half lives of the carbon-14 isotope in the dead organisms and calculate how many half life old the sample is. But as the years increases, the number of carbon-14 isotope becomes too low to detect and make accurate calculation.
This means, at some point the organism can simply run out of carbon-14.

Hence carbon-14 dating is not accurate for estimating age of materials older than 50,000 years old.

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Write a balanced equation to show the reaction of sulfurous acid with caesium hydroxide to form water and caesium sulfite.
Soloha48 [4]

Answer:

H2SO3 + 2CsOH —> Cs2SO3 + 2H2O

Explanation:

When sulfurous acid react with caesium hydroxide, caesium sulfite and water are formed according to the equation:

H2SO3 + CsOH —> Cs2SO3 + H2O

Next, we balanced the equation by putting 2 in front of CsOH and 2 in front of H2O i.e

H2SO3 + 2CsOH —> Cs2SO3 + 2H2O

5 0
3 years ago
Baker’s yeast catalyzes the decomposition of hydrogen peroxide (dihydrogen dioxide) into oxygen and water. Directions: Add 10 mL
andreev551 [17]

Answer:

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

Explanation:

  • Hydrogen peroxide is decomposed into oxygen and water, which is a slow reaction.
  • It is can be catalyzed by using yeast.

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

1.0 mol of H₂O₂ is decomposed to 1.0 mol of H₂O and 0.5 mol of O₂.

3 0
3 years ago
Calculate the molar mass of cacl2
kirza4 [7]

Answer:

\boxed {\boxed {\sf 110.98 \ g/mol}}

Explanation:

The molar mass is the mass of a substance in grams per mole.

To find it, add the mass of each element in the compound. These masses can be found on the Periodic Table.

The compound given is:

CaCl_2

The compound has 1 Ca (calcium) and 2 Cl (chlorine).

 

Mass of Calcium

  • The molar mass of calcium is 40.08 g/mol
  • There is only one atom of Calcium in CaCl₂, so the number above is what we will use.

Mass of Chlorine

  • The molar mass of chlorine is 35.45 g/mol
  • There are two atoms of chlorine in CaCl₂, therefore we need to multiply the molar mass by 2.
  • 35.45 * 2= 70.9 g/mol

Molar Mass of CaCl₂

  • Now, to find the molar mass, add the molar mass of 1 calcium and 2 chlorine.
  • 40.08 g/mol + 70.9 g/mol =110.98 g/mol

The molar mass of CaCl₂ is <u>110.98 grams per mole. </u>

6 0
3 years ago
If a ballon at 3.4 atm at 301k, what is the pressure when cooled to 212k
stepladder [879]

Answer:

2.39 atm

Explanation:

- Use Gay-Lussac's law

- P2 = P1T2/T1

- Fill in with our values

- Hope this helped! Please let me know if you need further explanation.

8 0
3 years ago
Compound A is an organic compound which contains Carbon, Hydrogen and Oxygen. When 0.240g of the vapour of A is slowly passed ov
vesna_86 [32]

(a)   In this section, give your answers to three decimal places.

(i)

Calculate the mass of carbon present in 0.352 g of CO

2

.

Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g

of

A

.

(ii)

Calculate the mass of hydrogen present in 0.144 g of H

2

O.

Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g

of

A

.

(iii)

Use your answers to calculate the mass of oxygen present in 0.240 g of

A

Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g

of

A


(b)

Use your answers to

(a)

to calculate the empirical formula of

A


thank you

hope it helpsss

4 0
3 years ago
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