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2 years ago

10

1. What is the relationship between pressure and volume?

2 answers:

blondinia [14]2 years ago

7 0

Pressure and volume are inversely proportional. Or Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship. If volume increases, then pressure decreases and vice versa, when the temperature is held constant.

MariettaO [177]2 years ago

5 0

Answer:

An increase in pressure would cause less volume and vice versa. They are inversely proportional.

Explanation:

This is due to Boyle's Law (and because an increase in pressure would increase the force on the container, however, if it's a closed container, it would burst)

<em>Feel free to mark it as brainliest :D</em>

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3 years ago

A 2.0 sample of N2 occupy 50.0L at 15 degrees Celsius and 640mmHg. What volume will the gas occupy at 45 degrees Celsius and 160

inysia [295]

Answer:

220.8L

Explanation:

Given parameters:

Initial volume = 50L

Initial temperature = 15°C = 288K

Initial pressure = 640mmHg

Final temperature = 45°C = 318K

Final pressure = 160mmHg

Unknown:

Final volume = ?

Solution:

Using the combined law;

$\frac{p_{1}v_{1} }{T_{1} }$ = $\frac{p_{2}v_{2} }{T_{2} }$

p,v and T are pressure, volume and Temperature

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v₂ = 220.8L

6 0

2 years ago

What is the delta H when 72.0 grams H2O condenses at 100.00C?

algol [13]

<u>Answer:</u> The value of $\Delta H$ is -163 kJZ

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

We are given:

Given mass of water = 72.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{72.0g}{18g/mol}\\\\\text{Moles of water}=4mol$

Calculating the heat released for the condensation process:

$\Delta H=n\times \Delta H_{(vap)}$ ......(2)

where,

$\Delta H$ = amount of heat released

n = number of moles of water = 4 moles

$\Delta H_{(vap)}$ = specific heat of vaporization = -40.7 kJ/mol

Negative sign represents the amount of heat released.

Putting values in equation 2:

$\Delta H=4mol\times (-40.7kJ/mol)=-163kJ$

Hence, the value of $\Delta H$ is -163 kJ

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2 years ago