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cricket20 [7]
3 years ago
5

Total atoms of each element in5CaCl2+3Ca(ClO4)2+4Ca(OH)2​

Chemistry
1 answer:
Monica [59]3 years ago
4 0

Answer:

Element   Symbol   Atomic Mass   # of Atoms  Mass Percent

Chlorine              Cl       35.453                             2        29.670%

Calcium                Ca     40.078                      1         16.770%

Oxygen                 O   15.9994                             8            53.559%                              

Explanation:

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What is the density of the marble when the mass = 10g
Marysya12 [62]
The density of marble is between 2.6 and 2.8 grams per cm³ .

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3 0
4 years ago
You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye
dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

V = 10 mL solution

V_{added} = 12.20 mL

V_{total} = 22.20 mL

then,

M 0.103 M of NaOH,

V_{rinsed} = experiment  will not be affected

V_{total \ base} = 10.38 mL

Now,

⇒  mol of NAOH = MV

                            = 0.103\times 10.38

                            =  1.06914  \ m

Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

⇒  mol \ of \ acid =\frac{1}{2}\times \ mol \   of  \ base

⇒  1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid

Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

                 =\frac{ 0.53457 }{10}

                 =0.053457 \ M (Sulfuric acid)

6 0
3 years ago
Write the balance chemical equation for propane.
Mars2501 [29]
It would be 3C + 4H2 -> C3H8
3 0
4 years ago
At what temperature (hot or cold) can we dissolve a gas in a solution
professor190 [17]

Depends on the gas and grams of solute. If you were able to give me a gas i would be able to help you but i cannot without the gas or chemical makeup.

4 0
3 years ago
There are 3.45 moles of (NH4)2 SO4, how many grams is this?
blsea [12.9K]

Answer:

455.4 g

Explanation:

Data given:

no. of moles of (NH₄)₂SO₄= 3.45 mol

mass of (NH₄)₂SO₄ = ?

Solution

Formula will be used

           no.of moles = mass in grams / molar mass

Rearrange the above equation for mass

           mass in grams = no. of moles x molar mass . . . . . . . . (1)

molar mass of (NH₄)₂SO₄

molar mass of (NH₄)₂SO₄ = 2(14 + 4(1)) + 32 + 4(16)

molar mass of (NH₄)₂SO₄ = 2 (14 +4) + 32 + 64  

molar mass of (NH₄)₂SO₄ = 2 (18) + 32 + 64

molar mass of (NH₄)₂SO₄ = 36 + 32 + 64 = 132 g/mol

Put values in equation 1

           mass in grams = 3.45 mole x 132 g/mol

           mass in grams = 455.4 g

So,

mass of (NH₄)₂SO₄ = 455.4 g

8 0
3 years ago
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