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12345 [234]
3 years ago
6

Compare and contrast gravitational potential energy and elastic potential energy.

Physics
1 answer:
enot [183]3 years ago
3 0

Answer:

Potential energy is energy that is stored in a person or object.Gravitational potential energy depends on an object's weight and its height above the ground (GPE = weight x height). Elastic potential energy is due to an object's shape. It results when an elastic object is stretched or compressed.

Explanation:

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True or false the state of a medium helps determine the speed of sound passing through a medium
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True. If a medium such as H2O is in ice form, sound can not pass through it as well as if it were water or water vapor
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3 years ago
What evidence suggests that Earth attracts or pulls on objects?
Contact [7]
Every object in the universe that has mass<span> exerts a gravitational pull, or </span>force<span>, on every other mass. </span>
5 0
4 years ago
Read 2 more answers
The Newton is the SI unit for ____.<br> temperature<br> mass<br> weight<br> density
mel-nik [20]

Answer:

weight

Explanation:

weight is measurd in newtons (N)

7 0
3 years ago
A cord is wrapped around the rim of a solid uniform wheel 0.300 m in radius and of mass 8.00 kg. A steady horizontal pull of 34.
disa [49]

Answer:

A. α = 94.4 rad/s

B. a = 28.32 m/s

C. N = 34N

D. α = 94.4 rad/s

    a = 28.32 m/s

     N =  44.4  N

Explanation:

part A:

using:

∑T = Iα

where T is the torque, I is the moment of inertia and α is the angular momentum.

firt we will find the moment of inertia I as:

I = \frac{1}{2}MR^2

Where M is the mass and R is the radius of the wheel, then:

I = \frac{1}{2}(8 kg)(0.3 m)^2

I = 0.36 kg*m^2

Replacing on the initial equation and solving for α, we get::

∑T = Iα

Fr = Iα

34 N =  0.36α

α = 94.4 rad/s

part B

we need to use this equation :

a = αr

where a is the aceleration of the cord that has already been pulled off and r is the radius of the wheel, so replacing values, we get:

a = (94.4)(0.3 m)

a = 28.32 m/s

part C

Using the laws of newton, we know that:

N = T

where N is the force that the axle exerts on the wheel part and T is the tension of the cord

so:

N = 34N

part D

The anly answer that change is the answer of the part D, so, aplying laws of newton, it would be:

-Mg + N +T = 0

Then, solving for N, we get:

N = -T+Mg

N = -34 + (8 kg)(9.8)

N =  44.4  N

6 0
3 years ago
How to change V=72km/hr to m/s
lapo4ka [179]
Multiply by (1000 meters / 1 km).
Then multiply by (1 hour / 3600 seconds).

Both of those fractions are equal to ' 1 ', because the top
and bottom numbers are equal, so the multiplications
won't change the VALUE of the 72 km/hr.  They'll only
change the units.

(72 km/hour) · (1000 meters / 1 km) · (1 hour / 3600 seconds)

= (72 · 1000 / 3600) (km·meter·hour / hour·km·second)

=  20 meter/second
7 0
4 years ago
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