Answer: Your question is missing below is the question
Question : What is the no-friction needed speed (in m/s ) for these turns?
answer:
20.1 m/s
Explanation:
2.5 mile track
number of turns = 4
length of each turn = 0.25 mile
banked at 9 12'
<u>Determine the no-friction needed speed </u>
First step : calculate the value of R
2πR / 4 = πR / 2
note : πR / 2 = 0.25 mile
∴ R = ( 0.25 * 2 ) / π
= 0.159 mile ≈ 256 m
Finally no-friction needed speed
tan θ = v^2 / gR
∴ v^2 = gR * tan θ
v = √9.81 * 256 * tan(9.2°) = 20.1 m/s
Answer:
a

b

Explanation:
From the question we are told that
The wavelength of the red light is 
The width of the slit is 
The distance of the screen from the point of diffraction is 
Generally the width of the central bright fringe is mathematically represented as
=>
=> 
Generally the width of the first bright fringe on either side of the central one is mathematically represented as

=> 
=> 
Answer:
we need it to work and without it we dont have strength to do anything