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Shtirlitz [24]
3 years ago
11

Water is boiled at 1 atm pressure in a 25-cm-internal- diameter stainless steel pan on an electric range. if it is observed that

the water level in the pan drops by 10 cm in 45 min, determine the rate of heat transfer to the pan.
Physics
1 answer:
patriot [66]3 years ago
3 0
<span>3933 watts At 100 C (boiling point of water), it's density is 0.9584 g/cm^3. The volume of water lost is pi * 12.5^2 * 10 = 4908.738521 cm^3 The mass of water boiled off is 4908.738521 * 0.9584 = 4704.534999 grams. Rounding to 4 significant figures gives me 4705 grams of water. The heat of vaporization for water is 2257 J/g. So the total energy applied is 2257 J/g * 4705 g = 10619185 J Now we need to divide that by how many seconds we've spent boiling water. That would be 45 * 60 = 2700 seconds. Finally, the rate of heat transfer in Joules per second will be the total number of joules divided by the total number of seconds. So 10619185 J / 2700 s = 3933 J/s = 3933 (kg m^2/s^2)/s = 3933 (kg m^2/s^3) = 3933 watts</span>
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The intensity of light from a star varies inversely as the square of the distance. If you lived on a planet ten times farther aw
frosja888 [35]

Answer:

the intensity of the sun on the other planet is a hundredth of that of the intensity of the sun on earth.

That is,

Intensity of sun on the other planet, Iₒ = (intensity of the sun on earth, Iₑ)/100

Explanation:

Let the intensity of light be represented by I

Let the distance of the star be d

I ∝ (1/d²)

I = k/d²

For the earth,

Iₑ = k/dₑ²

k = Iₑdₑ²

For the other planet, let intensity be Iₒ and distance be dₒ

Iₒ = k/dₒ²

But dₒ = 10dₑ

Iₒ = k/(10dₑ)²

Iₒ = k/100dₑ²

But k = Iₑdₑ²

Iₒ = Iₑdₑ²/100dₑ² = Iₑ/100

Iₒ = Iₑ/100

Meaning the intensity of the sun on the other planet is a hundredth of that of the intensity on earth.

3 0
4 years ago
Which physical activity would a global positioning system resource help you with?
PolarNik [594]

The physical activity that a global positioning system resource can help me with is : ( A )  Hiking

<h3>Function of Global positioning system ( GPS ) </h3>

GPS helps with the accurate measurement of physical activities  and factors such as location, time, elevation and so on. When hiking, the time, distance covered and location of the hiker  can be accurately measured with the use of the GPS.

Hence we can conclude that The physical activity that a global positioning system resource can help me with is  Hiking.

Learn more about GPS : brainly.com/question/9795929

#SPJ1

4 0
2 years ago
Urgent!
Masja [62]

mass of iron block given as

m_1 = 1.90 kg

density of iron block is

\rho = 7860 kg/m^3

now the volume of the iron piece is given as

V = \frac{m}{\rho}

V = \frac{1.90}{7860} = 2.42* 10^{-4} m^3

Now when this iron block is complete submerged in oil inside the beaker the buoyancy force on the iron block will be given as

F_b = \rho_L V g

here we know that

\rho_L = density of liquid = 916 kg/m^3

F_b = 916* 2.42 * 10^{-4} * 9.8

F_b = 2.17 N

Now for the reading of spring balance we can say the spring force and buoyancy force on the block will counter balance the weight of the block at equilibrium

F_s + F_b = mg

F_s + 2.17 = 1.90* 9.8

F_s = 16.45 N

So reading of spring balance will be 16.45 N

Now for other scale which will read the normal force of the surface we can write that normal force on the container will balance weight of liquid + container and buoyancy force on block

F_n = F_g + F_b

F_n = (1 + 2.50)*9.8 + 2.17

F_n = 34.3 + 2.17 = 36.47 N

So the other scale will read 36.47 N

3 0
4 years ago
Which statement about allele combinations is accurate?
Pepsi [2]

Offspring get two alleles for each trait – one from each parent.

6 0
3 years ago
A 55.0-kg skydiver drew falls for a period of time before opening his parachute. what is his kinetic energy when he reaches a ve
Jlenok [28]
Mass (m)=55kg

acceleration (a)=9.81 m/s^2, this is the acceleration due to gravity.

initial velocity=0m/s. The skydiver doesn’t start with any speed because she is on the plane or helicopter.

final velocity=16m/s This is the velocity (speed) the skydiver reaches

The equation we use is KE=.5mv^2
Kinetic energy=.5 mass x velocity^2

KE=.5(55kg)(16m/s)^2
KE=.5(55kg)(256m/s)
KE=.5(14080J)

J=Joules

KE=7040J

Kinetic energy is 7040 Joules (J)

Hope this helps
3 0
4 years ago
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