Water is boiled at 1 atm pressure in a 25-cm-internal- diameter stainless steel pan on an electric range. if it is observed that
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Given :
Two forces act on a 6.00-kg object. One of the forces is 10.0 N.
Acceleration of object 2 m/s².
To Find :
The greatest possible magnitude of the other force.\
Solution :
Let, other force is f.
So, net force, F = 10 + f.
Now, acceleration is given by :
Therefore, the greatest possible magnitude of the other force is 2 N.
Hence, this is the required solution.
Actually what the problem meant about the westward component of the ball’s displacement is the horizontal component of the displacement. To help us better understand the problem, I attached a figure of the situation.
We can see from the figure that to solve for the value of the horizontal component, we have to make use of the sin function. That is:
sin θ = side opposite to the angle / hypotenuse of the triangle
sin 42 = x / 40 m
x = (40 m) sin 42
x = 26.77 m
Therefore the ball has a westward displacement of about 26.77 m
