Answer:
the weight of the rider is 493.53 N
Explanation:
Given the data in the question and as illustrated in the image below,
Tension T = 1900 N
the rider is moving at a constant speed so the net force in the horizontal direction will be 0
In the horizontal direction
Fcos( 30° ) = Tcos ( 17° )
F = Tcos( 17° ) / cos( 30° )
F = 1900cos( 17° ) / cos( 30° )
F = 2098.07 N
Now, In the vertical direction,
F sin( 30° ) = W + T sin( 17° )
W = F sin( 30° ) - T sin( 17° )
W = 2098.07sin( 30° ) - 1900sin( 17° )
W = 1049.035 - 555.506
W = 493.53 N
Therefore, the weight of the rider is 493.53 N
