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3 years ago

Computer-enhanced x-rays are called __________ scans. A. TMS B. PET C. CT D. MRI

Physics

2 answers:

saul85 [17]3 years ago

5 0

Answer:

I think the answer is C

Explanation:

EDGE 2020

goldenfox [79]3 years ago

3 0

Answer:

C. CT

Explanation:

It stands for Computed Tomography Scans.

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A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on the free end of the rope f

Taya2010 [7]

The range of force exerted at the end of the rope is 285.7 N to 1,000 N.

<h3>Net horizontal force of the cylinder</h3>

The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.

∑F = 0

F - μFn = 0

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force increases as the number of turns of the rope increases.

minimum force = total force/number of turns of rope

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

Learn more about Newton's second law of motion here: brainly.com/question/3999427

8 0

2 years ago

When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmin

Papessa [141]

Answer:

The number of liters of ice water is 11 L

Explanation:

Given data:

normal body temperature = 37°C

temperature of the ice water = 0°C

Cwater = specific heat of water = 4186 J/kg °C

Suppose the person drinks 1 L of cold water, then, the mass is 1 kg

The heat is:

$Q_{water} =mC_{water} (T_{ice} -T_{body} )=1*4186*(0-37)=-154882J$

The sign (-) indicates the energy lost by the metabolic process. If the Qwalk is 390 kilocalories, then the number of liters of ice water is equal to:

$n=\frac{Q_{walk} }{Q_{water} } =\frac{390*4186}{154882} =10.54=11L$

5 0

3 years ago

The most pressing problem in the Chesapeake Bay is

densk [106]

Answer:

The answer is C. Pollution

3 0

3 years ago

Read 2 more answers

A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.

MrRissso [65]

Answer:

(a). The distance is 49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

$d=u\cos\theta\times t$

Put the value into the formula

$d=20\cos40\times3.25$

$d=49.79\ m$

(b). We need to calculate the horizontal velocity

Using formula of velocity

$v_{x}=u\cos\theta$

Put the value into the formula

$v_{x}=20\times\cos40$

$v_{x}=15.3\ m/s$

We need to calculate the vertical velocity

Using equation of motion

$v_{y}=u\sin\theta-gt$

Put the value into the formula

$v_{y}=20\sin40-9.8\times3.25$

$v_{y}=-19\ m/s$

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

$v=\sqrt{v_{x}^2+v_{y}^2}$

$v=\sqrt{(15.3)^2+(19)^2}$

$v=24.39\ m/s$

Hence, (a). The distance is 49.79 m.

(b). The speed of the ball is 24.39 m/s.

4 0

3 years ago

a fast humvee drove from desert a to desert b. for the 12 hours, it travelled at an speed of 185 km/h. for the next 13 hours, it

ivanzaharov [21]

Answer:

I am not sure of the question?

Explanation:

List the question

8 0

3 years ago