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mylen [45]
3 years ago
10

17. Matthew has a piece of wood with mass of 278 g and a volume of 375 cm^3. What is the wood’s density? a. Step 1: Formula ____

__________________________ b. Step 2: Data m = _________, v = ________ c. Step 3: Solve d = = ___________
Physics
1 answer:
Keith_Richards [23]3 years ago
8 0

Answer:

Density =0.74 g/cm^{3}

Explanation:

Step 1: Formula

 Density=\frac{Mass}{Volume}

Step 2: Data

m=278 g

v=375 cm^{3}

Step 3:Solve

d= \frac{278}{375} g/cm^{3}

d=0.74 g/cm^{3}

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Please help Need good grade
ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the  range

Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

Here, distance and speed are same

On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

6 0
4 years ago
Two buses are driving along parallel freeways that are 5mi apart, one heading east and the other heading west. Assuming that eac
Oksanka [162]

Answer:

101.54m/h

Explanation:

Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;

Let l be the be the distance further away at which they will meet from the current points;

l=\sqrt{13^2-5^2}=12m\\\\\frac{dl}{dt}=-(55m/h+55m/h})\\\\=-110m/h#The speed toward each other.

\frac{dh}{dt}=0, \ \ \ \ h=constant\\\\h^2+l^2=b^2\\\\2h\frac{dh}{dt}+2l\frac{dl}{dt}=2b\frac{db}{dt}\\\\2\times5\times0+2\times12\times(-110)=2\times13\frac{db}{dt}\\\\\frac{db}{dt}=-101.54m/h

Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h

4 0
3 years ago
Which statement is true of a glass lens that diverges light in air?
Arisa [49]
C it is uniformly thick
3 0
3 years ago
Read 2 more answers
An athlete is running a 400m race around a 400m track. On the backstretch the athlete's velocity is 8m/s but he is running into
Aleksandr-060686 [28]

Answer:

33 N

Explanation:

v = Velocity of fluid = 8+2 = 10 m/s

\rho = Density of fluid = 1.2 kg/m³

C = Coefficient of drag = 1.1

A = Cross sectional area = 0.5 m²

Drag force is given by

F=\frac{1}{2}\rho CAv^2\\\Rightarrow F=\frac{1}{2}\times 1.2\times 1.1\times 0.5\times (8+2)^2\\\Rightarrow F=33\ N

The drag force on the athlete is 33 N

3 0
3 years ago
How can a karate expert break a concrete block
FinnZ [79.3K]

Many ways, but some of the most famous are kicks (side, back, front, snap) or a smash.

Hope it helped! :)

8 0
3 years ago
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