= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)
= -0.00225 m
New length = L + ΔL
= 1.25 m + (-0.00225 m)
= 1.248
D
17. Matthew has a piece of wood with mass of 278 g and a volume of 375 cm^3. What is the wood’s density? a. Step 1: Formula ____
1 answer:
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= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)
= -0.00225 m
New length = L + ΔL
= 1.25 m + (-0.00225 m)
= 1.248
D
We know that -
Where,
First we convert height into meters.
1 km = 1000 meters
3 km = 1000 * 3 meters = 3000 meters
So, putting the values in the above formula, and by taking 'g' = 9.8 m/s², we get-
Where,
First we convert height into meters.
1 km = 1000 meters
3 km = 1000 * 3 meters = 3000 meters
So, putting the values in the above formula, and by taking 'g' = 9.8 m/s², we get-
Answer:
So coefficient of kinetic friction will be equal to 0.4081
Explanation:
We have given mass of the block m = 0.5 kg
The spring is compressed by length x = 0.2 m
Spring constant of the sprig k = 100 N/m
Blocks moves a horizontal distance of s = 1 m
Work done in stretching the spring is equal to
This energy will be equal to kinetic energy of the block
And this kinetic energy must be equal to work done by the frictional force
So
So coefficient of kinetic friction will be equal to 0.4081