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Nat2105 [25]
4 years ago
12

The composition of the universe only consists of 596 of ordinary matter. True O False

Physics
2 answers:
brilliants [131]4 years ago
6 0
True
Because I know lol they make u type so much
mash [69]4 years ago
3 0
The answer would be true
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is dimensionally correct relation necessarily to be a correct physical relation? explain with example.​
Andreas93 [3]

Answer: hope it helps you...❤❤❤❤

Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.

No, not necessarily.

For instance, Newton’s 2nd law is  F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.

But take a look at this (incorrect) equation for the force of gravity:

F=−G(m+M)Mm√|r|3r  

It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for  G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.

It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.

A simpler counter example is  1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.

4 0
4 years ago
What is the speed of the object at the end of 10 s?
Ostrovityanka [42]

Answer:

-100m/s not shure tho thx tho

6 0
3 years ago
how could a person easily tell which letters had four and which rive pages without opening the envelope? what assumptions did yo
Lubov Fominskaja [6]
Had 4 what and when you said rive did u mean 5
5 0
4 years ago
In the Bohr model of the hydrogen atom, an electron orbits a proton in a circular orbit of radius 0.53 X 10^-10 m. What is elect
maxonik [38]

Answer:

a) 27.2 V

b)27.2 V

Explanation:

Charge of the electron =charge of the proton = q = 1.6 × 10⁻¹⁹ C

Radius = r = 0.53×10⁻¹⁰ m

Electric Potential = V = k q/r

k = 9 ×10⁹ N m²/C² = Coulomb's constant.

V = (9 ×10⁹)(1.6 × 10⁻¹⁹)/( 0.53×10⁻¹⁰) = 27.2 V

b) Potential Energy of the electron =  k q × q / r

   = [(9 ×10⁹)(1.6 × 10⁻¹⁹)(1.6 × 10⁻¹⁹) / (0.53×10⁻¹⁰)] / (1.6 × 10⁻¹⁹) eV,

since 1 electron volt = (1.6 × 10⁻¹⁹)joules

   = 27.2 eV

7 0
4 years ago
H2+O2=H2O<br><br> need to balance the chemical equation
yuradex [85]

Answer:

2         1         2

Explanation:

5 0
3 years ago
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