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babunello [35]
3 years ago
9

A 1/4 inch 16 UNC bolt is tumed by a 8-inch wrench a robotic arm.

Engineering
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

A. The pitch of the bolt is 0.0625 inch

B. The IMA of the screw is approximately 12.57

Explanation:

A. The given information from the specification of the bolt are;

The major diameter, D, of the bolt = 1/4 inch

The number of threads per inch = 16 threads

The pitch of a bolt is he distance between each successive thread which is found by dividing a unit length by the number of threads of bolt in the unit length

Therefore;

The pitch of the bolt = 1 inch/(The number of threads per inch) = 1 inch/(16 threads per inch) = 0.0625 inch

The pitch, P, of the bolt = 0.0625 inch

B. The Ideal Mechanical Advantage (IMA) of the screw is given as follows;

IMA = The circumference of the screw/(The pitch of the screw)

IMA = π × D/P = π × 1/4 inch/(0.0625 inch) ≈ 12.57

The IMA ≈ 12.57

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Ceramics has the weakness of resisting high compression force but low tensile force. a)-True b)-False
Nesterboy [21]

Answer: b) False

Explanation:Ceramic is brittle in nature therefore it has a tendency that it is strong during the compression and it tends to be weak during the high tensile forces. While the tensile forces are applied , ceramics are not able to yield the stress and cause breakage of the material due to high tension but does not face any fault during the compression.

7 0
4 years ago
Consider the following incomplete code segment, which is intended to print the sum of the digits in num. For example, when num i
ValentinkaMS [17]

Answer:

A) while (num >= 0)

Explanation:

To understand why we need to focus on the module and division operation inside the loop. num % 10 divide the number by ten and take its remainder to then add this remainder to sum, the important here is that we are adding up the number in reverse order and wee need to repeat this process until we get the first number (1%10 = 1), therefore, num need to be one to compute the last operation.

A) this is the correct option because num = 1 > 0 and the last operation will be performed, and after the last operation, num = 1 will be divided by 10 resulting in 0 and 0 is not greater than 0, therefore, the cycle end and the result will be printed.

B) This can not be the option because this way the program will never ends -> 0%10 = 0 and num = 0/10 = 0

C) This can not be the option because num = 1 > 1 will produce an early end of the loop printing an incomplete result

D) The same problem than C

E) There is a point, before the operations finish, where sum > num, this will produce an early end of the loop, printing an incomplete result

6 0
3 years ago
Cool water at 15°C is throttled from 5(atm) to 1(atm), as in a kitchen faucet. What is the temperature change of the water? What
Tresset [83]

Answer:

the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg

Explanation:

Given that:

Initial Temperature T_1 = 15°C

Initial Pressure P_1 = 5 atm

Final Pressure P_2 = 1 atm

Data obtain from steam tables of saturated water at  15°C are as follows:

Specific volume  v = 1.001 cm³/gm

The change in temperature = 2°C

Specific heat of water = 4.19 J/gm.K

volume expansivity β = 1.5 × 10⁻⁴ K⁻¹

The expression to determine the change in temperature can be given as :

\delta \ T = \frac{-V (1- \beta \ T}{C_p} * \delta \ P ( \frac{1}{9.87} \ \frac{J}{cm^3/atm})\delta \ T = \frac{-1.001 \frac{cm^3}{gm} (1- 1.5*10^{-4} \  K^{-1} )*2}{4.19 \ \frac{J}{gm.K}} *(5-1)atm ( \frac{1}{9.87} \ \frac{J}{cm^3/atm})

Δ T = 0.093 K

Now; we can calculate the lost work bt the formula:

W_{lost} = T_{surr} *S

where ;

T_{surr} is the temperature of the surrounding. = 20°C = (20+273.15)K =  293.15 K

From above the change in entropy is:

\delta \  S = C_p \  In (\frac{T+ \delta \ T }{T}) *  \beta V \delta P

\delta \  S = 4.19*  \  In (\frac{288.15+0.093 }{288.15}) -  1.5*10^{-4} * 1.001 (5-1)* (\frac{1}{9.87})

\delta \  S =1.408*10^{-3} \ J/gm.K

W_{lost} = T_{surr} *S

W_{lost} = 293.15* 1.408*10^{-3} \ J/gm.K

W_{lost} = 0.413 \  kJ/kg

Thus, the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg

6 0
4 years ago
What is the most likely cause a brake light staying on?
Monica [59]
The answer is either a or b
8 0
3 years ago
Oliver is designing a new children’s slide to increase the speed at which a child can descend. His first design involved steel b
AVprozaik [17]

Answer:

The correct option is;

A) Steel becomes too hot in the Sun and can burn the children

Explanation:

The properties of steel includes;

Low specific heat capacity, high thermal and electrical toughness, high hardness, high tensile strength, high yield strength, appreciable elongation, high fatigue strength, can easily corrode, high malleability and ability to creep

Therefore, due to the low specific heat capacity, which is 0.511 J/(g·°C) and high conductivity of steel which is about 32 W/(m·k), the temperature of the steel can rapidly rise and the hot steel surface can readily conduct the heat, (due to the temperature difference) to other bodies that come in contact

8 0
3 years ago
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