Answer:
The weight should be added to the base of the sign to keep it from tipping is 65.6 lb
Explanation:
Given data:
A sigh weighs 40 pounds
Suported by an 18 in x 18 in square
Force of the wind 13.2 lb
Questions: Will the sign tip over, if yes, how much evelnly distributed weight should be added to the base of the sign to keep it from tipping, W = ?
The sign and the post have a length of 6 ft. You need to calculate the distance from the edge to the middle point:
18/2 = 9 in = 0.75 ft
Force acting in the base (40 lb):
The weight should be added to the base:
Answer:
the required diameter of the rod is 9.77 mm
Explanation:
Given:
Length = 1.5 m
Tension(P) = 3 kN = 3 × 10³ N
Maximum allowable stress(S) = 40 MPa = 40 × 10⁶ Pa
E = 70 GPa = 70 × 10⁹ Pa
δ = 1 mm = 1 × 10⁻³ m
The required diameter(d) = ?
a) for stress
The stress equation is given by:
A is the area = πd²/4 = (3.14 × d²)/4
Substituting the values, we get
d = (9.77 × 10⁻³) m
d = 9.77 mm
b) for deformation
δ = (P×L) / (A×E)
A = (P×L) / (E×δ) = (3000 × 1.5) / (1 × 10⁻³ × 70 × 10⁹) = 0.000063
d² = (4 × A) / π = (0.000063 × 4) / 3.14
d² = 0.0000819
d = 9.05 × 10⁻³ m = 9.05 mm
We use the larger value of diameter = 9.77 mm
Explanation:
The square cut seal is what allows the caliper piston to retract back into its housing. Just because you can manually push the piston in, doesn't mean the square cut seal is working. Rapid brake pad wear, brake drag or brake pull are key indicators that the square cut seal is comprised
Answer:
forward voltage triggering
temperature triggering
dv/dt triggering
light triggering
gate triggering
Then turning off;
Turn off is accomplished by a "negative voltage" pulse between the gate and cathode terminals
Explanation:
hope it helps
