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4 years ago

11

Ceramics has the weakness of resisting high compression force but low tensile force. a)-True b)-False

1 answer:

Nesterboy [21]4 years ago

7 0

Answer: b) False

Explanation:Ceramic is brittle in nature therefore it has a tendency that it is strong during the compression and it tends to be weak during the high tensile forces. While the tensile forces are applied , ceramics are not able to yield the stress and cause breakage of the material due to high tension but does not face any fault during the compression.

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For some transformation having kinetics that obey the Avrami equation (Equation 11.17), the parameter n is known to have a value

Nastasia [14]

Explanation:

Below is an attachment containing the solution.

5 0

3 years ago

19/32 reduced to its lowest form

d1i1m1o1n [39]

Answer:

19/32

Explanation:

19/32 is already in its lowest form

8 0

3 years ago

Read 2 more answers

1. Two aluminium strips and a steel strip are to be bonded together to form a composite bar. The modulus of elasticity of steel

yarga [219]

Answer:

1.933 KN-M

Explanation:

<u>Determine the largest permissible bending moment when the composite bar is bent horizontally </u>

Given data :

modulus of elasticity of steel = 200 GPa

modulus of elasticity of aluminum = 75 GPa

Allowable stress for steel = 220 MPa

Allowable stress for Aluminum = 100 MPa

a = 10 mm

<em>First step </em>

determine moment of resistance when steel reaches its max permissible stress

<em>next </em>: determine moment of resistance when Aluminum reaches its max permissible stress

Finally Largest permissible bending moment of the composite Bar = 1.933 KN-M

<em>attached below is a detailed solution </em>

5 0

3 years ago

Can anyone help me ?

MrRa [10]

That’s too hard for me lol oof

3 0

3 years ago

While supporting load P, the maximum contraction permitted in a 4.75-m long pipe column is 7 mm. Given that E =180 GPa for the c

Alexeev081 [22]

Answer:

$\mathbf{stress \ \sigma = 264.6 \ Mpa}$

Explanation:

From the concept of Hooke's Law,

$E =\dfrac{ stress \ \sigma}{ strain \ \varepsilon}$

where;

$strain \ \varepsilon = \dfrac{change \ in \ dimension }{original \ dimension}$

$strain \ \varepsilon = \dfrac{7 \ mm }{4.75 \times 10^{3} \ mm}$

$strain \ \varepsilon =0.00147368$

Recall:

$E =\dfrac{ stress \ \sigma}{ strain \ \varepsilon}$

$stress \ \sigma = E \times { strain \ \varepsilon}$

$stress \ \sigma = 180 \times 10^{3} \ Mpa \times 0.00147$

$\mathbf{stress \ \sigma = 264.6 \ Mpa}$

Thus, the stress in the pipe at the maximum allowable contraction = 264.6 Mpa

7 0

3 years ago