4 years ago

The best way to check the efficiency of individual cylinders is:________.

Engineering

1 answer:

KATRIN_1 [288]4 years ago

8 0

Answer:

To run. The machine one at a time

Explanation:

You might be interested in

At steady state, air at 200 kPa, 325 K, and mass flow rate

Vera_Pavlovna [14]

Letra A

A letra

A.
Thank

3 0

3 years ago

Fill in the tables and find the equivalent resistance for the following circuits:

Dafna11 [192]

Answer:

12 32

Explanation:

3 0

2 years ago

Ideias de nomes para um gato (macho), foto no anexo.

Rzqust [24]

So cute! xxxxxxxxxxxxxxxxx

4 0

3 years ago

A three-story school has interior column bays that are spaced 25 ft apart in both directions. If the loading on the flat roof is

Lady_Fox [76]

Answer:

Explanation:

Floor Load:

Lo= 50psf

At= 25x25 = 625 square feet

$L= Lo(0.25 +15/\sqrt{KuAt)}$

$L=50(0.25+15/\sqrt{(4)(625)}$ = 13.1psf

%reduction= 13.1/50 = 26%

Fr= 3[(13.1psf)(25ft)(25ft)+(20psf)(25ft)(25ft)]= 62k

7 0

3 years ago

The ???? − i relationship for an electromagnetic system is given by ???? = 1.2i1/2 g where g is the air-gap length. For current

Artemon [7]

Answer:

a) The mechanical force is -226.2 N

b) Using the coenergy the mechanical force is -226.2 N

Explanation:

a) Energy of the system:

$\lambda =\frac{1.2*i^{1/2} }{g} \\i=(\frac{\lambda g}{1.2} )^{2}$

$\frac{\delta w_{f} }{\delta g} =\frac{g^{2}\lambda ^{3} }{3*1.2^{2} }$

$f_{m}=- \frac{\delta w_{f} }{\delta g} =-\frac{g^{2}\lambda ^{3} }{3*1.2^{2} }$

If i = 2A and g = 10 cm

$\lambda =\frac{1.2*i^{1/2} }{g} =\frac{1.2*2^{1/2} }{10x10^{-2} } =16.97$

$f_{m}=-\frac{g^{2}\lambda ^{3} }{3*1.2^{2} }=-\frac{16.97^{3}*2*0.1 }{3*1.2^{2} } =-226.2N$

b) Using the coenergy of the system:

$f_{m}=- \frac{\delta w_{f} }{\delta g} =-\frac{1.2*2*i^{3/2} }{3*g^{2} }=-\frac{1.2*2*2^{3/2} }{3*0.1^{2} } =-226.2N$

8 0

3 years ago