1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zmey [24]
2 years ago
8

I need you to solve for me plzzzzzz

Chemistry
1 answer:
Sergeu [11.5K]2 years ago
3 0

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

Finally, the answer will be .0556 L.

<h3 />
You might be interested in
Which of the following is one part of a chemical formula?
melomori [17]

Answer:

C

Explanation:

You would be correct in guessing C as in a chemical formula symbol of each element is stated.

Like Salt is Sodium Chloride, and its chemical formula is NaCl (Na=sodium, Cl= chloride)

7 0
3 years ago
Sucrose, a major product of photosynthesis in green leaves, is synthesized by a battery of enzymes. The substrates for sucrose s
Gwar [14]

Answer:

Sucrose is a disaccharide composed of alpha D gluose and beta D fructose linked together by beta 2,alpha1 glycosidic linkage.

Explanation:

The specificity of glycosidic linkage very much essential to choose the substrate for the synthesis of specific disaccharide.

 For example sucrose contain beta 2,alpha1 glycosidic linkage that means the hydroxyl group of anomeric carbon of one monosaccharide(fructose) should remain in beta conformation and the hydroxyl group of other monosaccharide(glucose) should remain in alpha conformation.

   

5 0
3 years ago
How many atoms are in a sample of 1.83 moles of potassium (K) atoms? Please explain the conversions to me. Thank you!
IRINA_888 [86]
1 mole K ------------- 6.02x10²³ atoms
1.83 moles K ------ ?? atoms

1.83 x (6.02x10²³) / 1 =

1.101x10²⁴ atoms of K

hope this helps!
6 0
3 years ago
Who wants to be mine
andrew11 [14]

hellow! how r you? 。◕‿◕。

Explanation:

nice to know you then:)

8 0
2 years ago
Consider the following data showing the initial rate of a reaction (A→products) at several different concentrations of A.
OlgaM077 [116]

Answer:

(1) order = 2

(2) R = K [A]²

Explanation:

Given the reaction:

A--------->Product

The rate constant relation for the reaction is given as:

R(i) = K [A]............(*)

Where R(I) is rate constant at different concentration of A.

Taking the rate constant as R1, R2 and R3 for the different concentrations respectively. Then the following equations results

0.011 = K [0.15] ⁿ.........(1)

0.044 = K [0.30]ⁿ .......(2)

0.177 = K [0.60]ⁿ .........(3)

Dividing (2) by (1) and (3) by (1)

Gives:

0.044/0.011 = [0.3/0.15]ⁿ

4 = 2ⁿ; 2² = 2ⁿ; n = 2

Similarly

0.177/0.011 = [0.60/0.15]ⁿ

16.09 = 4ⁿ

16.09 = 16 (approximately)

4² = 4ⁿ ; n = 2

Hence the order of the reaction is 2.

The rate law is R = K [A]²

4 0
3 years ago
Other questions:
  • A motor “runs” when what is produced by a spinning magnet ?
    12·1 answer
  • A sample of gas starts at 1.00 atm, 0.00 degrees Celsius, and 30.0 mL. What is the volume if the temperature increases to 27.0 d
    10·1 answer
  • What process would farmers use to produce vegetables that will grow in a specific climate?
    5·1 answer
  • How is bohrs model of the atom arranged? where the protons? nuetrons? electrons?
    5·2 answers
  • Looking at a potential energy diagram what is the name given to represent the amount of energy given off during an exothermal re
    10·1 answer
  • A 10 kg bicycle is rolling down a hill at 5 m/s, what is its momentum?
    11·1 answer
  • The photograph shows one of the boats in a science club's toy boat race. All the boats were powered by identical
    10·2 answers
  • Aplicaciones del agua pesada en medicina
    8·2 answers
  • What is the random mixing of gas molecules called?
    15·2 answers
  • Can someone do my homework pls!
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!