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3 years ago

Which of the following is one part of a chemical formula?

Chemistry

1 answer:

melomori [17]3 years ago

7 0

Answer:

Explanation:

You would be correct in guessing C as in a chemical formula symbol of each element is stated.

Like Salt is Sodium Chloride, and its chemical formula is NaCl (Na=sodium, Cl= chloride)

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Plz help it’s due very soon

Setler79 [48]

Answer:

192g

Explanation:

so for this find out there moles of CH4 by moles=mass/mr

48/16=3 then use molar ratio 1:2 so times it by 2 which is 6 moles. then uses mass =moles*mr so 6*32=192g is the answer hope this helps to understand.

5 0

3 years ago

Read 2 more answers

What does the number represent in the isotope platinum-194?

vazorg [7]

The number in isotope platinum-194 stands for the <em>total </em>amount of protons and neutrons. In other words, this is the mass. =)

4 0

3 years ago

You start out with 800 moles of a radioactive substance. After 24 hours, 100 moles remain. What is the half-life of the substanc

Nookie1986 [14]

The half life of the substance is 8 hours , Option D is the correct answer.

What is Half Life ?

Half-life is the time required by an unstable element to reduce to half of its initial value.

The term is commonly used in nuclear physics.

The formula is

$\rm N(t) = \; N_{0} \;(\dfrac{1}{2} )^{\frac{t}{t_{1/2} } }$

N(t) = quantity of the substance remaining

N ₀ = initial quantity of the substance

t = time elapsed

$\rm t_{1/2}$ = half life of the substance

The data given in the question is N ₀ = 800 moles , N(t)= 100 , t= 24 hours

$\rm t_{1/2} =\; ?$

Substituting values in the equation

$\rm 100 = \; 800 \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }$

$\rm \dfrac{100}{800} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm \dfrac{1}{8} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm (\dfrac{1}{2})^{3} = \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm 3=\dfrac{24}{t_{1/2} }\\\\t_{1/2}= \dfrac{24}{3}\\\\t_{1/2} = 8 hours$

Therefore half life of the substance is 8 hours , Option D is the correct answer.

To know more about Half Life

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3 0

2 years ago

Match the prefix used in naming binary molecule compounds with its corresponding number

VARVARA [1.3K]

Nona= 9, hepta= 7, hexa= 6, tetra= 4

8 0

3 years ago

If 12.8 g lead(II) sulfate (303.3 g/mol) precipitates when excess potassium chloride is added to 1.65 L of a water sample, what

quester [9]

Answer:

$M=0.0256M$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$PbSO_4(aq)+2KCl(aq)\rightarrow PbCl_2(s)+K_2SO_4(aq)$

In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:

$n_{Pb^{2+}}=12.8gPbSO_4*\frac{1molPbSO_4}{303.3gPbSO_4} *\frac{1molPb^{2+}}{1molPbSO_4} \\\\n_{Pb^{2+}}=0.0422molPb^{2+}$

Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:

$M=\frac{n_{Pb^{2+}}}{V}=\frac{0.0422molPb^{2+}}{1.65L}\\ \\M=0.0256M$

Regards.

5 0

3 years ago