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Sati [7]
3 years ago
6

A buret is a device designed to precisely dispense liquids. The scale is calibrated in mL with the zero point at the top with nu

mbers increasing down the buret. Assuming the buret was filled to 0.00 mL, determine the liquid volume dispensed by reading the buret pictured below, taking care to record the proper number of significant figures consistent with the design of the buret.
Engineering
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer:

As there was no attached picture, I will explain how to take the measurement of liquids in any buret which you can then apply to the specific question

Explanation:

A buret is a  laboratory apparatus used to precisely measure the volume of liquids (usually alkalise or bases) used in a titration experiment. The standard buret has a capacity of 50 ml  and graduated in 0.1ml though burets with smaller capacities exist.

From the question, your buret is filled to the top (0.00ml) with liquid. It is very important when taking buret readings to place the buret below your eye level so that the bottom meniscus (lower part of the liquid) can be read.

To take the buret reading, note your initial buret reading (in this case 0.00ml) then titrate the liquid base in the buret against the acid by opening the tap located at the bottom of the buret.

When the titration or reaction is complete, note the final reading against the calibration of buret. You can do this by observing the lower meniscus of the liquid remaining in the buret. (Remember to keep the buret at eye level  to avoid parallax error),

The difference between your final buret reading and the initial buret reading gives you the precise volume of liquid used in the reaction.

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3 years ago
An open-open organ pipe is 73.5 cm long. An open-closed pipe has a fundamental frequency equal to the third harmonic of the open
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Answer:

The length of the  open closed pipe is 12.25 cm

Explanation:

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The length of the open-open organ pipe is equal to the sum of wavelength in Antinode to Node, Node to Node, Node to Node and Node to Antinode.

L = A→N + N→N + N→N + N→A

L =\frac{\lambda }{4} + \frac{\lambda }{2} + \frac{\lambda }{2} + \frac{\lambda }{4} \\\\L = \frac{ 3\lambda }{2}\\\\\lambda = \frac{2L}{3} \\\\F = \frac{V}{\lambda} = \frac{3V}{2L}

In open-closed pipe, Fundamental frequency has Antinode to Node.

Thus, length of the open-closed organ pipe is equal to the wavelength in Antinode to Node.

L = A→N

L_o = \frac{\lambda}{4} \\\\\lambda =4L_o\\\\F_o = \frac{V}{4L_o}

From the information in the question, fundamental frequency of open-closed pipe is to the third harmonic of the open-open pipe.

F₀ = F

\frac{V}{4L_o} =\frac{3V}{2L} \\\\\frac{1}{4L_o} = \frac{3}{2*73.5 \ cm}\\\\\frac{1}{L_o} = \frac{3*4}{2*73.5 \ cm}\\\\\frac{1}{L_o}  = \frac{12}{147 \ cm}\\\\L_o =  \frac{147 \ cm}{12} = 12.25 \ cm

Therefore, the length of the  open closed pipe is 12.25 cm

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