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Fofino [41]
3 years ago
8

In an ecosystem, a wide range of organisms coexist. In a pond ecosystem, one can find amoebae, bacteria, green algae, and fish.

Which of the
following is the best conclusion one can make regarding the genetic diversity of these organisms?
Green algae will have the greatest genetic diversity because they are photosynthetic and do not depend on other organisms to survive.
Fish will have the greatest genetic diversity because they receive genetic material from a male and female source.
Bacteria will have the greatest genetic diversity because their high reproductive rate ensures that some will survive.
Amoebae will have the greatest genetic diversity because their genetic makeup allows them to survive in many environments.
Biology
2 answers:
nydimaria [60]3 years ago
8 0

Answer:

The correct answer would be "Fish will have the greatest genetic diversity because they receive genetic material from a male and female source".

Genetic diversity is defined as the variation in the total amount of genetic information among the individual of the population.

In sexually reproducing population, genetic diversity is present in high amount as compared to asexually reproducing population.

It is because of two reasons:

The genetic make of an individual is determined by 2 parents (father and mother).

The event of crossing over takes place during formation of gametes.

Together, they lead to the development of new combinations of alleles in an offspring which is different from both the parents.

Thus, fish would have the highest genetic diversity in their population.

Explanation:

rjkz [21]3 years ago
6 0

Answer: Progressives introduced reforms to address the ills of industrial capitalism. Their efforts led to anti-trust law suits (e.g., Northern

Explanation:

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Q1. The answer is 1.

It can be calculated using the equation:

 (1/2)ⁿ = x

x - decimal amount remaining, 

n - a number of half-lives.


x = 50% = 50/100 = 0.5

n = ?

(1/2)ⁿ = 0.5

log((1/2)ⁿ) = log(0.5)

n * log(1/2) = log(0.5)

n * log(0.5) = log(0.5)

n = log(0.5)/log(0.5)

n = 1


Q10. The answer is 2.


It can be calculated using the equation:

 (1/2)ⁿ = x

x - decimal amount remaining, 

n - a number of half-lives.


Rhyolite #2 has 25% of the parent H remaining:

x = 25% = 25/100 = 0.25

n = ?

(1/2)ⁿ = 0.25

log((1/2)ⁿ) = log(0.25)

n * log(1/2) = log(0.25)

n * log(0.5) = log(0.25)

n = log(0.25)/log(0.5)

n = -0.602 / - 0.301

n = 2



Q3. The answer is 100 million years.


A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):

n = t/H

n = 1

t = ?

H = 100 000 000 years


n = t/H

t = n * H

t = 1 * 100 000 000 years

t = 100 000 000 years<span>

</span>

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