Answer:
The specific heat of the alloy
Explanation:
Mass of an alloy = 25 gm
Initial temperature = 100°c = 373 K
Mass of water = 90 gm
Initial temperature of water = 25.32 °c = 298.32 K
Final temperature = 27.18 °c = 300.18 K
From energy balance equation
Heat lost by alloy = Heat gain by water
[ - ] = ( - )
25 × × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)
This is the specific heat of the alloy.
Answer:
Explanation:
Because the image of the graduated cylinder in your question was not attached when sending it in, I have attached one which I would use to explain the answer given.
In taking readings of liquids from a measuring cylinder, you must be at eye level from the apparatus, after which you are to take reading from below the meniscus (the lower curve) of the water.
From the image I attached, that would be 24ml.
Please apply the following to your image. I hope this was helpful.