How many atoms are there in a sample of lead with a mass of 6.8 g?

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

Phoenix [80]

Answer:

The volume of the gas at given temperature is $1300 cm^3$

Explanation:

$P_1$ = initial pressure of gas = 1 atm

$T_1$ = initial temperature of gas = $0^oC=273.15 K$

$V_1$ = initial volume of gas = $310 cm^3 = 310 mL = 0.310 L$

( $1 cm^3= 1mL$ , 1 mL = 0.001 L)

$P_1V_1=nRT_1$ ..[1]

$P_2$ = final pressure of gas = 2.1 atm

$T_2$ = final temperature of gas = $2,200^oC=273+2200 K=2473.15 K$

$V_2$ = final volume of gas = ?

$P_2V_2=nRT_2$ ..[2]

By dividing [1] and [2] we get combined gas equation :,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}$

Now put all the given values in the above equation, we get:

$V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}$

$V_2=1.3 L=1300 mL= 1300 cm^3$

The volume of the gas at given temperature is $1300 cm^3$

3 0

3 years ago

Read 2 more answers

What is the percent composition of CuO if a sample of CuO with a mass of 62.5 g contains 12.5 g of oxygen (O) and 50 g of Cu

Arlecino [84]

Percent (%) Composition of CuO

Cu = 1 x 50g - Multiply by one as there is one Cu

O = 1 x 12.5g - Multiply by one as there is one O

CuO = 62.5g

% for Cu = 50g over 62.5 multiplied by 100 = 80%

% for O = 12.5g over 62.5 multiplied by 100 = 20%

Final Answer :

Percent (%) Composition of CuO = 80% (Cu) & 20% (O)

7 0

3 years ago

Which elements in the periodic table are metalloids or have semimetallic properties?

inessss [21]

B, As only are metalloids or have semimetallic properties.

3 0

3 years ago

Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {

sashaice [31]

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH+, and OH-?

b) Calculate Kb for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH⁻] = 10∧(-2,67) = 0,00213 M.
[OH⁻] = [C₁₀H₁₅NOH⁺] = 0,00213 M.
[C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.
Kb = [OH⁻] · [C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].
Kb = (0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.

3 0

3 years ago

“Least molecular motion, lowest kinetic energy, strongest forces of attention, most dense packaging of molecules”. Which state o

SashulF [63]

<h2>Solid. Because molecules densely packed it has a high resistance to flow thereby lower kinetic energy. </h2>

8 0

3 years ago