According to the question, the object is placed at 2F
The ray diagram is shown in the figure attached.
According to the figure:
Object AB is at 2F₁
First, we draw a ray parallel to principal axis.
So, it passes through focus after refraction.
We draw another ray which passes through optical center.
So, the ray will go through without any deviation.
Where both refracted rays meet is point A' and the image formed is A'B'
This image is formed at 2F₂
We can say that:
- Image is real.
- Image is inverted.
- Image is exactly the same size as the object.
Answer:
Explanation:
Given that, .
Pressure around scuba is
P = 10^5 Pa
1 Pa = 1 N/m²
Then
P = 10^5 N/m²
Descending height
h = 10m
Change in force per unit square centimetre
We know that,
Pressure = Force / Area
Then,
Force / Area is the required question we are finding
Then,
Force / Area = 10^5 N / m²
So, let convert the m² to cm²
100cm = 1m
(100cm)² = (1m)²
10⁴cm² = 1m²
Then,
Force / Area = 10^5 N/m² × 1m² / 10⁴cm²
Force / Area = 10 N/cm²
So, the force per unit square centimeters is 10.
Answer:
That would be a perpetual motion machine
Explanation:
Answer:
33.2 m
Explanation:
For the first object:
y₀ = 81.5 m
v₀ = 0 m/s
a = -9.8 m/s²
t₀ = 0 s
y = y₀ + v₀ t + ½ at²
y = 81.5 − 4.9t²
For the second object:
y₀ = 0 m
v₀ = 40.0 m/s
a = -9.8 m/s²
t₀ = 2.20 s
y = y₀ + v₀ t + ½ at²
y = 40(t−2.2) − 4.9(t−2.2)²
When they meet:
81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²
81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)
81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716
81.5 = 61.56t − 111.716
193.216 = 61.56t
t = 3.139
The position at that time is:
y = 81.5 − 4.9(3.139)²
y = 33.2
Hey ／人 ◕ ‿‿ ◕ 人＼
The answer is transmission
uses a series of gears to transmit power to facilitate changes in speed .
GLAD TO HELP
~~~ ╔͎═͓═͙╗
~~~ ╚̨̈́═̈́﴾ ̥̂˖̫˖̥ ̂ )
