Question

How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you need this solution at pH 9.0 is anything else required? (2 pts)

Answer 1

Explanation:

The given data is as follows.

        Concentration of solution = 0.5 M

        Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = $\frac{\text{No. of moles}}{\text{Volume}}$

Hence, calculate the number of moles as follows.

            No. of moles = Molarity × Volume

                                  = $0.5 M \times 1 L$

                                  = 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

                                                      = $0.5 mol \times 132.119 g/mol$

                                                      = 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.