On oxidation of aldehydes produces carboxylic acid functional group.
The product of oxidation of aldehydes depends upon whether the reaction occur in acidic medium or alkaline condition.
If oxidation of aldehydes occurs under acidic condition the product is carboxylic acid but if oxidation of aldehydes occurs under alkaline condition then reduce as well as oxidized product obtained which is known as disproportional product.
The oxidation of aldehydes occur through potassium dichromate, potassium permanganate or many more. The oxidation of aldehydes in the presence of base is known as cannizzaro's reaction.
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<span>In order for Drix to stay in Frank's body, he will need a lawyer. Ozzie (Osmosis Jones) suggests that "we'll go down to the hemorrhoid and get you a good lawyer."</span>
Answer is: increase the concentration of NiCO₄ and <span>withdraw CO from the products as it is forming.
Balanced chemical reaction: NiCO</span>₄(g) ⇄ Ni(s) + 4CO(g).
According to Le Chatelier's Principle the position of equilibrium
moves to counteract the change:
1) the position of equilibrium will move to the right, so
that the concentration of nickel carbonyl gas decreases again and produce more nickel.
2) the position of equilibrium will move to the right, if we decrease concentration of carbon monoxide, more nickel carbonyl gas will decompose and produce more nickel.
<h3>
Answer:</h3>
4.227 × 10^-19 Joules
<h3>
Explanation:</h3>
Energy of a photon of light is calculated by the formula;
E = hf, where h is the plank's constant, 6.626 × 10^-34 J-s and f is the frequency.
But, f = c/λ
Where, c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength.
Given the wavelength is 470 nm or 4.7 × 10^-7 m
Therefore;
E = hc/λ
= (6.626 × 10^-34 J-s × 2.998 × 10^8 m/s) ÷ 4.7 × 10^-7 m
= 4.227 × 10^-19 Joules
Therefore, the energy of a photon with 470 nm is 4.227 × 10^-19 Joules
