The answer for this question is 0.8
Answer:
The answer to your question is: 69.6 %
Explanation:
Freon -112 (C₂Cl₄F₂)
MW = (12 x 2) + (35.5 x 4) + (19 x 2)
= 24 + 142 + 38
= 204 g
204 g of C₂Cl₄F₂ ----------------- 100%
142 g ----------------- x
x = (142 x 100 ) / 204
x = 69.6 %
Answer:
The answer to your question is: a = 2.1 m/s²
Explanation:
Data
Acceleration : ?
Mass = 2000 kg
Force = 4200 N
Formula
Newton's second law of motion F = ma
a = F / m
Substitution
a = 4200 N / 2000 kg
a = 2.1 m/s²
Answer:
Pressure for H₂ = 11.9 atm
Option 5.
Explanation:
We determine the complete reaction:
2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
As we do not know anything about the HCl, we assume that the limiting reactant is the Al and the acid is the excess reagent.
Ratio is 2:3.
2 moles of Al, can produce 3 moles of hydrogen
Therefore 4.5 moles of Al must produce (4.5 . 3) / 2 = 6.75 moles
Now we can apply the Ideal Gases law to find the H₂'s pressure
P . V = n . R . T → P = (n . R .T) / V
We replace data: (6.75 mol . 0.082L.atm/mol.K . 300K) / 14L
Pressure for H₂ = 11.9 atm
Answer:
The total pressure is 1.616 atm
Explanation:
First of all we say:
In a closed system, sum of partial pressures is the value for the total pressure.
In our system, we have gas A and B
Total pressure without the third gas is = 0.373 atm + 0.650 atm = 1.023 atm
As we add a third gas, with no change in volume or T°, let's find out by the Ideal Gases Law, its pressure:
P . V = n . R . T
P = ( n . R . T) / V
P = (0.220 mol . 0.082 . (273 + 21°C)) / 8.95L = 0.593 atm
273 + 21°C → Absolute value of T°
Let's sum the partial pressures, then:
0.373 atm + 0.650 atm + 0.593 atm = 1.616 atm.
It's ok to say that the total pressure was increased, because we have more gas now.
