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3 years ago

In what way is Model B better than Model A?

Physics

2 answers:

Varvara68 [4.7K]3 years ago

4 0

Answer: Option (B) is the correct answer.

Explanation:

When model B shows three dimensional shape of the molecule then it becomes easier to visualize the exact shape or geometry of the molecule as we get to know how atoms are bonded together.

Therefore, with the help of this it would be easy to know the hybridization of molecule. Basically, we will get to know the type of molecule represented by model B.

Thus, we can conclude that the statement Model B shows the three-dimensional shape of the molecule, but Model A does not represents Model B better than Model A.

vekshin13 years ago

3 0

on edg202p it is C

got a 90 on my test

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elena55 [62]

Explanation:

It is given that,

Mass of an electron, $m=9.11\times 10^{-31}\ kg$

Initial speed of the electron, $u=3\times 10^5\ m/s$

Final speed of the electron, $v=7\times 10^5\ m/s$

Distance, d = 5 cm = 0.05 m

(a) The acceleration of the electron is calculated using the third equation of motion as :

$a=\dfrac{v^2-u^2}{2d}$

$a=\dfrac{(7\times 10^5)^2-(3\times 10^5)^2}{2\times 0.05}$

$a=4\times 10^{12}\ m/s^2$

Force exerted on the electron is given by :

$F=m\times a$

$F=9.11\times 10^{-31}\times 4\times 10^{12}$

$F=3.64\times 10^{-18}\ N$

(b) Let W is the weight of the electron. It can be calculated as :

$W=mg$

$W=9.11\times 10^{-31}\times 9.8$

$W=8.92\times 10^{-30}\ N$

Comparison,

$\dfrac{F}{W}=\dfrac{3.64\times 10^{-18}}{8.92\times 10^{-30}}$

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4 years ago

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Answer:

The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.

Explanation:

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3 years ago

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4 years ago

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Answer:

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Explanation:

Given that,

Speed of wind = 75.0 km/hr

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Using formula of angle

$\sin\theta=\dfrac{v'}{v}$

Where, v'=speed of wind

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$\theta=\sin^{-1}(\dfrac{75}{310})$

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