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antoniya [11.8K]
3 years ago
13

Give an example of intense aerobics activity. Prompt must be accurate. ​

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

Explanation:

An example of an intense aerobic activity would be running/ sprinting sprinting targets six specific muscle groups: hamstrings, quadriceps, glutes, hips, abdominals and calves. Sprinting is a total body workout featuring short, high-intensity repetitions and long, easy recoveries.

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The equation for momentum is p=mv. Which letter represents the momentum? Question 2 options: p m v
vovikov84 [41]
P stands for momentum
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4 years ago
How far will a man travel in 15 min driving his car down the highway at an average speed of 24 m/?s
emmasim [6.3K]

Answer:

21.6 km

Explanation:

15×60×24 = 21600 m

\frac{21600}{1000}= 21.6 km

7 0
3 years ago
Help! <br><br><br>I'm not sure my answer is correct.<br><br><br>Problem is attached!​
kaheart [24]
  • Let G be xN

\\ \sf\longmapsto x-20=30

\\ \sf\longmapsto x=30+20

\\ \sf\longmapsto x=50N

Option B

3 0
3 years ago
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Two point charges are separated by a distance of 1 meter. How much would the force change if one charge was 4x larger?
jekas [21]

Answer:

the force would increase 4 times more

Explanation

more force results more mass or acceleration

6 0
3 years ago
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A solid 200-g block of lead and a solid 200-g block of copper are completely submerged in an aquarium filled with water. Each bl
finlep [7]

Answer:

B. The buoyant force on the copper block is greater than the buoyant force on the lead block.

Explanation:

Given;

mass of lead block, m₁ = 200 g = 0.2 kg

mass of copper block, m₂ = 200 g = 0.2 kg

density of water, ρ = 1 g/cm³

density of lead block, ρ₁ = 11.34 g/cm³

density of copper block, ρ₂ = 8.96 g/cm³

The buoyant force on each block is calculated as;

F_B = mg(\frac{density \ of \ fluid}{density \ of \ object} )

The buoyant force of lead block;

F_{lead} = 0.2*9.8(\frac{1}{11.34} )\\\\F_{lead} = 0.173  \ N

The buoyant force of copper block

F_{copper} = 0.2*9.8(\frac{1}{8.96})\\\\F_{copper} = 0.219  \ N

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block

3 0
3 years ago
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