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ddd [48]
3 years ago
15

Two blocks of the same mass but made of different material slide across a horizontal, rough surface and eventually come to rest.

A graph of the kinetic energy of each block as a function of position along the surface . Which of the following is a true statement about the frictional force Ff that is exerted on the two blocks?
a. Fr=2F8, since the force of friction is represented as the slope for each of the two curves.
b. Fr.-12Fri, since the force of friction is represented as the inverse slope for each of the two curves.
c. Ff:=2Ffi, since the force of friction is represented as the inverse of the area bound by each curve and th horizontal axis.
d. Fe=1/2Fr., since the force of friction is represented as the area bound by each curve and the horizontal axis.
Physics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

a. \mathbf{F_{f_2} = 2 F_{f1}}, \mathbf { since \ the \ force \ o f \ friction  \ is \ represented  \ as  \ the \  slope \ for \ each  \ of  \ the \ two  \ curves.}

Explanation:

From the information given;

Using the work-energy theorem

ΔKE = W = \mathbf{ F_f \times r}

K = \mathbf{ F_f \times r}

∴

\dfrac{K_1}{K_2} = \dfrac{F_{f1}}{F_{f2}} (\dfrac{r_1}{r_2})

Since K_1 = K_2 and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

Then;

1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})

\mathbf{F_{f_2} = 2 F_{f1}}

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Answer:

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Explanation:

Given that,

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Diffraction of first order is defined as,

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The separation of the slits

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Now put the value in equation (I)

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Here, n = 1

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4 years ago
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Answer: D

Explanation:

Atomic weight is measured by adding the number of protons and neutrons in an atom's nucleus. Argon's atomic number is 18 while potassium's is 19. This means that Argon will always have 18 protons while potassium will always have 19 protons.

To make the numbers easier to work with, round each atomic weight. We'll say the atomic weight of potassium is 39 and the atomic weight of argon is 40. To see how many neutrons each one has, I can set up a simple equation for each using the following equation:

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Argon:

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