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ddd [48]
3 years ago
15

Two blocks of the same mass but made of different material slide across a horizontal, rough surface and eventually come to rest.

A graph of the kinetic energy of each block as a function of position along the surface . Which of the following is a true statement about the frictional force Ff that is exerted on the two blocks?
a. Fr=2F8, since the force of friction is represented as the slope for each of the two curves.
b. Fr.-12Fri, since the force of friction is represented as the inverse slope for each of the two curves.
c. Ff:=2Ffi, since the force of friction is represented as the inverse of the area bound by each curve and th horizontal axis.
d. Fe=1/2Fr., since the force of friction is represented as the area bound by each curve and the horizontal axis.
Physics
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

a. \mathbf{F_{f_2} = 2 F_{f1}}, \mathbf { since \ the \ force \ o f \ friction  \ is \ represented  \ as  \ the \  slope \ for \ each  \ of  \ the \ two  \ curves.}

Explanation:

From the information given;

Using the work-energy theorem

ΔKE = W = \mathbf{ F_f \times r}

K = \mathbf{ F_f \times r}

∴

\dfrac{K_1}{K_2} = \dfrac{F_{f1}}{F_{f2}} (\dfrac{r_1}{r_2})

Since K_1 = K_2 and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

Then;

1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})

\mathbf{F_{f_2} = 2 F_{f1}}

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A planet is discovered orbiting around a star in the galaxy Andromeda at the same distance from the star as Earth is from the Su
aniked [119]

Answer:

The planet´s orbital period will be one-half Earth´s orbital period.

Explanation:

The planet in orbit, is subject to the attractive force from the sun, which is given by the Newton´s Universal Law of Gravitation.

At the same time, this force, is the same centripetal force, that keeps the planet in orbit (assuming to be circular), so we can put the following equation:

Fg = Fc ⇒ G*mp*ms / r² = mp*ω²*r

As we know to find out the orbital period, as it is the time needed to give a complete revolution around the sun, we can say this:

ω = 2*π / T (rad/sec), so replacing this in the expression above, we get:

Fg = Fc ⇒   G*mp*ms / r² = mp*(2*π/T)²*r

Solving for T²:

T² = (2*π)²*r³ / G*ms (1)

For the planet orbiting the sun in Andromeda, we have:

Ta² = (2*π)*r³ / G*4*ms (2)

As the radius of the orbit (distance to the sun) is the same for both planets, we can simplify it in the expression, so, if we divide both sides in (1) and (2), simplifying common terms, we finally get:

(Te / Ta)² =  4  ⇒ Te / Ta = 2 ⇒ Ta = Te/2

So, The planet's orbital period will be one-half Earth's orbital period.

7 0
3 years ago
From different frames of reference, time intervals and lengths both appear different. what is one measurement that will appear t
choli [55]

The speed of a beam of light will appear the same to all observers.

<h3>Speed of light:</h3>

The exact distance that light travels in a vacuum in a second is 299,792,458 meters (983,571,056 feet). This is roughly 186,282 miles per second, or "c," the symbol for light speed in mathematics.

According to Einstein's theory of special relativity, an object (such as a single photon of light) cannot appear to move faster than the speed of light. This physical rule is not broken by Nemiroff's experiment since the laser pointer emits a stream of photons rather than a single photon.

Nothing can move faster than light in a vacuum, according to one of physics' most revered rules. However, in a recent experiment, this speed restriction was broken when a laser pulse traveled at more than 300 times the speed of light.

Learn more about speed here:

brainly.com/question/13202563

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6 0
2 years ago
What is the resistance force when you walk up an inclined plane?<br> Please help quick!
Dominik [7]
Friction
Friction also affects the movement of an object on a slope. Friction is a force that offers resistance to movement when one object is in contact with another. Imagine now that you were on the downside of the object and applying force to keep the object in the same place (not moving)
5 0
3 years ago
A skater rotates with her arms crossed at an angular speed of 8.0 rad/s and she has a moment of inertia of 100 kg/m2. She extend
solong [7]

Answer:

When her hands extends, her momen of inertia is 4.28\ kg-m^2.

Explanation:

Given that,

Initial angular speed, \omega_i=8\ rad/s

Initial moment of inertia, I_1=100\ kg-m^2

Final angular speed, \omega_f=7\ rad/s

Initially, a skater rotates with her arms crossed and finally she extends her arms. The momentum remains conserved. Using the conservation of momentum as :

I_1\omega_1=I_2\omega_2

I_2 is final moment of inertia

I_2=\dfrac{I_1\omega_1}{\omega_2}\\\\I_2=\dfrac{100\times 8}{7}\\\\I_2=114.28\ kg-m^2

So, when her hands extends, her momen of inertia is 4.28\ kg-m^2. Hence, this is the required solution.

7 0
3 years ago
2342-24521+2453x=1342
Dmitry [639]

Answer:

9.59

Explanation:

Given expression:

       2342  - 24521 + 2453x  = 1342

Now,

    add similar terms on both sides of the expression:

              -22179 + 2453x  = 1342

 So;

  Collect like terms;

              2453x  = 1342 + 22179

               2453x  = 23521

 Now, divide both sides by 2453;

              x  = 9.59

3 0
3 years ago
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