Answer:
The answer is "
".
Explanation:
Its minimum velocity energy is provided whenever the satellite(charge 4 q) becomes 15 m far below the square center generated by the electrode (charge q).
![U_i=\frac{1}{4\pi\epsilon_0} \times \frac{4\times4q^2}{\sqrt{(15)^2+(5/\sqrt2)^2}}](https://tex.z-dn.net/?f=U_i%3D%5Cfrac%7B1%7D%7B4%5Cpi%5Cepsilon_0%7D%20%5Ctimes%20%5Cfrac%7B4%5Ctimes4q%5E2%7D%7B%5Csqrt%7B%2815%29%5E2%2B%285%2F%5Csqrt2%29%5E2%7D%7D)
It's ultimate energy capacity whenever the satellite is now in the middle of the electric squares:
![U_f=\frac{1}{4\pi\epsilon_0}\ \times \frac{4\times4q^2}{( \frac{5}{\sqrt{2}})}](https://tex.z-dn.net/?f=U_f%3D%5Cfrac%7B1%7D%7B4%5Cpi%5Cepsilon_0%7D%5C%20%5Ctimes%20%5Cfrac%7B4%5Ctimes4q%5E2%7D%7B%28%20%5Cfrac%7B5%7D%7B%5Csqrt%7B2%7D%7D%29%7D)
Potential energy shifts:
![= U_f -U_i \\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{\sqrt{(15)^2+( \frac{5}{\sqrt{2})^2)}}\right ) \\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{ 15 +( \frac{5}{2})}}\right )\\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{ (\frac{30+5}{2})}}\right )\\\\](https://tex.z-dn.net/?f=%3D%20U_f%20-U_i%20%5C%5C%5C%5C%20%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%5Csqrt2%7D%7B5%7D-%5Cfrac%7B1%7D%7B%5Csqrt%7B%2815%29%5E2%2B%28%20%5Cfrac%7B5%7D%7B%5Csqrt%7B2%7D%29%5E2%29%7D%7D%5Cright%20%29%20%5C%5C%5C%5C%20%20%20%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%5Csqrt2%7D%7B5%7D-%5Cfrac%7B1%7D%7B%2015%20%2B%28%20%5Cfrac%7B5%7D%7B2%7D%29%7D%7D%5Cright%20%29%5C%5C%5C%5C%20%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%5Csqrt2%7D%7B5%7D-%5Cfrac%7B1%7D%7B%20%28%5Cfrac%7B30%2B5%7D%7B2%7D%29%7D%7D%5Cright%20%29%5C%5C%5C%5C)
![=\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{ (\frac{35}{2})}}\right )\\\\=\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{17.5}}\right )\\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{ 24.74- 5 }{87.5}}\right )\\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{ 19.74- 5 }{87.5}}\right )\\\\ =\frac{4q^2}{\pi\epsilon_0}\left ( 0.2256 }\right )\\\\= \frac{0.28 \times q^2}{ \epsilon_0}\\\\=q^2\times31.35 \times10^9\,J](https://tex.z-dn.net/?f=%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%5Csqrt2%7D%7B5%7D-%5Cfrac%7B1%7D%7B%20%28%5Cfrac%7B35%7D%7B2%7D%29%7D%7D%5Cright%20%29%5C%5C%5C%5C%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%5Csqrt2%7D%7B5%7D-%5Cfrac%7B1%7D%7B17.5%7D%7D%5Cright%20%29%5C%5C%5C%5C%20%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%2024.74-%205%20%7D%7B87.5%7D%7D%5Cright%20%29%5C%5C%5C%5C%20%3D%5Cfrac%7B16q%5E2%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%20%5Cfrac%7B%2019.74-%205%20%7D%7B87.5%7D%7D%5Cright%20%29%5C%5C%5C%5C%20%3D%5Cfrac%7B4q%5E2%7D%7B%5Cpi%5Cepsilon_0%7D%5Cleft%20%28%200.2256%20%7D%5Cright%20%29%5C%5C%5C%5C%3D%20%5Cfrac%7B0.28%20%5Ctimes%20q%5E2%7D%7B%20%5Cepsilon_0%7D%5C%5C%5C%5C%3Dq%5E2%5Ctimes31.35%20%5Ctimes10%5E9%5C%2CJ)
Now that's the energy necessary to lift a satellite of 100 kg to 300 km across the surface of the earth.
![=\frac{GMm}{R}-\frac{GMm}{R+h} \\\\=(6.67\times10^{-11}\times6.0\times10^{24}\times100)\left(\frac{1}{6400\times1000}-\frac{1}{6700\times1000} \right ) \\\\ =(6.67\times10^{-11}\times6.0\times10^{26})\left(\frac{1}{64\times10^{5}}-\frac{1}{67\times10^{5}} \right ) \\\\=(6.67\times6.0\times10^{15})\left(\frac{67 \times 10^{5} - 64 \times 10^{5} }{ 4,228 \times10^{5}} \right ) \\\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7BGMm%7D%7BR%7D-%5Cfrac%7BGMm%7D%7BR%2Bh%7D%20%5C%5C%5C%5C%3D%286.67%5Ctimes10%5E%7B-11%7D%5Ctimes6.0%5Ctimes10%5E%7B24%7D%5Ctimes100%29%5Cleft%28%5Cfrac%7B1%7D%7B6400%5Ctimes1000%7D-%5Cfrac%7B1%7D%7B6700%5Ctimes1000%7D%20%5Cright%20%29%20%5C%5C%5C%5C%20%3D%286.67%5Ctimes10%5E%7B-11%7D%5Ctimes6.0%5Ctimes10%5E%7B26%7D%29%5Cleft%28%5Cfrac%7B1%7D%7B64%5Ctimes10%5E%7B5%7D%7D-%5Cfrac%7B1%7D%7B67%5Ctimes10%5E%7B5%7D%7D%20%5Cright%20%29%20%5C%5C%5C%5C%3D%286.67%5Ctimes6.0%5Ctimes10%5E%7B15%7D%29%5Cleft%28%5Cfrac%7B67%20%5Ctimes%2010%5E%7B5%7D%20-%2064%20%5Ctimes%2010%5E%7B5%7D%20%20%7D%7B%204%2C228%20%5Ctimes10%5E%7B5%7D%7D%20%5Cright%20%29%20%5C%5C%5C%5C)
![=( 40.02\times10^{15})\left(\frac{3 \times 10^{5}}{ 4,228 \times10^{5}} \right ) \\\\ =40.02 \times10^{15} \times 0.0007 \\\\](https://tex.z-dn.net/?f=%3D%28%2040.02%5Ctimes10%5E%7B15%7D%29%5Cleft%28%5Cfrac%7B3%20%5Ctimes%2010%5E%7B5%7D%7D%7B%204%2C228%20%5Ctimes10%5E%7B5%7D%7D%20%5Cright%20%29%20%5C%5C%5C%5C%20%3D40.02%20%5Ctimes10%5E%7B15%7D%20%5Ctimes%200.0007%20%5C%5C%5C%5C)
![\\\\ =0.02799\times10^{10}\,J \\\\= q^2\times31.35\times10^{9} \\\\ =0.02799\times10^{10} \\\\q=0.0945\,C](https://tex.z-dn.net/?f=%5C%5C%5C%5C%20%3D0.02799%5Ctimes10%5E%7B10%7D%5C%2CJ%20%5C%5C%5C%5C%3D%20q%5E2%5Ctimes31.35%5Ctimes10%5E%7B9%7D%20%5C%5C%5C%5C%20%3D0.02799%5Ctimes10%5E%7B10%7D%20%5C%5C%5C%5Cq%3D0.0945%5C%2CC)
This satellite is transmitted by it system at a height of 300 km and not in orbit, any other mechanism is required to bring the satellite into space.
Answer:
Dynamic flexibility
Explanation:
Dynamic flexibility can be generally defined as the ability of the body muscles and joints to move in full range of motion. High flexibility in these joints and muscles leads to the decreasing pain and injury in different parts of the body.
Proper warm up exercises are needed to be carried out that involves both the combination of controlling movements and stretching of the body, and this directly enhances the dynamic flexibility of the body.
The athletes and sports persons possesses a good dynamic flexibility of their body as they carry our different types of body exercises.
Answer:
If thermal energy is the motion energy of the particles of a substance, which has more thermal energy—the cup of hot tea or a spoonful of hot tea? It makes sense that the more particles of a substance you have, then the more thermal energy the substance has. The cup of hot tea would have more thermal energy, even if the temperature of the tea is the same in the cup and in the spoon. But which cools down the quickest (has the highest rate of thermal energy transfer)—the tea in the cup or the tea in the spoon? If I have fewer particles of the same substance, then the rate of thermal energy transfer is faster. The tea in the spoon would lose thermal energy more rapidly. So the amount of a substance you have is one factor that affects the rate of thermal energy transfer.
Explanation: