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konstantin123 [22]
3 years ago
15

Four wires meet at a junction. In two of the wires, currents and enter the junction. In one of the wires, current leaves the jun

ction. Find the current in the fourth wire and indicate its direction.
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

Explanation:

Kirchoff's current law: It states that the total current entering at a junction is equal to the total current leaving at the junction. It isbased on conservation of charge.  

As two current i1 and i2 is entering at the junction and i3 is leaving, so the current in forth wire is

i4 = i1 + i2 - i3

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In what direction must a force be applied so that the forces on the 1 kg object are balanced
choli [55]

Answer:

towards the object

Explanation:

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3 years ago
Which combination of temperature and pressure correctly describes standard temperature and pressure
raketka [301]

Answer: A combination 0 degrees Celsius and 101.3 kPa or 1 atm correctly describes standard temperature and pressure.

Explanation:

The term standard temperature and pressure is also known as STP and it is most commonly used when we want to calculate the density of a gas.

The term standard temperature means 32^{o} Fahrenheit or 0^{o}C or 273 Kelvin. On the other hand, term standard pressure means 1 atmosheric pressure of a gas.

Thus, we can conclude that a combination 0 degrees Celsius and 101.3 kPa or 1 atm correctly describes standard temperature and pressure.

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3 years ago
A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from
ladessa [460]

Answer:

P_1 = 1166.7 Watt

P_2 = 2000 Watt

Explanation:

Average power for the human sprinter is given as

Power = \frac{\Delta E}{\Delta t}

so we have

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(70)(10^2) - 0}{3}

P_1 = 1166.7 Watt

Average power for greyhound is given as

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(30)(20^2) - 0}{3}

P_2 = 2000 Watt

3 0
3 years ago
What is the specific heat of an object if it takes 1200 J to raise the temperature of a 20 kg object by 6 degrees C?
ch4aika [34]

Answer:

c=10\ J/kg^{\circ} C

Explanation:

Given that,

Heat required, Q = 1200 J

Mass of the object, m = 20 kg

The increase in temperature, \Delta T=6^{\circ} C

We need to find the specific heat of the object. The heat required to raise the temperature is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{1200}{20\times 6}\\\\c=10\ J/kg^{\circ} C

So, the specific heat of the object is 10\ J/kg^{\circ} C.

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3 years ago
What would spines be helpful for?
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A and c...............................
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