Answer:
The distance is 
Explanation:
From the question we are told that
The coefficient of static friction is 
The initial speed of the train is 
For the crate not to slide the friction force must be equal to the force acting on the train i.e

The negative sign shows that the two forces are acting in opposite direction
=> 
=> 
=> 
=> 
From equation of motion

Here v = 0 m/s since it came to a stop
=> 
=> 
=> 
D.
50 mph - 30 mph= 20 mph net velocity
change.
20mph/3600 seconds/hour= .00555 MPS
.0055 miles per second
40 seconds to complete the change
.0055/40= .000138
<h3>
Answer:</h3>
<h3>
Explanation:</h3>
_______________
S=3 m²
F=900 N
_______________
p - ?
_______________
p=F/S=900 N / 3 m² = 300 Pa
Answer:
25 m/s
Explanation:
This question can be solved using equation of motion

where
v is the final velocity
u is the initial velocity
s is the distance covered while moving from initial to final velocity
a is the acceleration
_____________________________________________
Given
box moved for distance of 62.5 m
Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.
thus in this problem
a = -5.0 m/s2
V = 0 as body came to rest due to friction deceleration
u the initial velocity we have to find
the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.
so if we find speed of box, we will be able get sped of truck as well.
using equation of motion

Thus, initial speed with the truck was travelling was 25 m/s.