Answer:
C2, C1, C4, C5 and C6 are in parallel. Therefore, we use the formula Cp = C1 + C2 + ....
Cp = C2 + C1 + C4 + C5 + C6 = ( 7 * 10 ^-3) + (18 * 10^-6) + (0.8F) + (200 * 10^-3 F) + (750 * 10^-6) = 1.008F
Now, Cp will become one capacitor and it will be aligned with C3, therefore it will now become a circuit in series.
We use the formula: 1/Cs = 1/C1 + 1/C2 + .... + ....1/Cn
Thus,
1/Cs = 1/C3 + 1/Cp
1/Cs = 1/(14 * 10^-3 F) + 1/(1.008F)
Cs = 1.4 * 10 ^-2 or if we do not round too much it will give exactly 0.0138 F
So the answer should be a)
The wave diagramed in blue.
Answer:
k = 7.32 N/m
Explanation:
We know that the time period of a spring mass system is given as follows:
T = 2π√(m/k)
T² = 4π²m/k
k = 4π²m/T²
where,
k = force constant = ?
m = mass = 0.019 kg
T = Time Period = 0.32 s
Therefore,
k = 4π²(0.019 kg)/(0.32 s)²
<u>k = 7.32 N/m</u>
Answer:
B.
The explanation of the relationship between load and extension is not in Hooke's Law.
Explanation:
