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3 years ago

Use the following photoelectric graph to answer the following question:

Physics

1 answer:

8090 [49]3 years ago

8 0

Answer:

2.9 E14 Hz

Explanation:

As we know by Einstein's equation that energy incident on the photo sensitive surface will be used by the surface to eject electron out of the surface with some kinetic energy.

This is given by

$E = \phi + KE$

now the threshold frequency is the minimum frequency of the incident photons due to which electrons are ejected out with minimum kinetic energy or least kinetic energy.

So here when KE = 0 in the graph then corresponding to that position the frequency will be given as threshold frequency

so here from graph when KE = 0

$f = 2.9 E14 Hz$

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$\Phi = \frac{2\pi \delta}{\lambda}$

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