Answer:
Centripetal acceleration of this aircraft: approximately 
.
Distance covered during the turn: approximately 
.
Time required for the turn: approximately 
(approximately 
.)
Explanation:
Convert velocity and radius to standard units:
.
.
Hence, the centripetal acceleration of this aircraft:
.
The trajectory of the turn is an arc with a radius of 
and a central angle of 
. The length of this arc would be:
.
The time required to travel at a speed of 
would be:
.
Answer:
The new force on the test charge is 145.02N
Explanation:
Force on a unit positive charge can be calculated using coulomb's law.
F =Kq²/r²
Where
F is the force on the charge = 321 N
K is a constant = 8.99 X10⁹ Nm²/C²
q is a test charge = 4.89 μC = 4.89 X10⁻⁶ C
r is the distance between the charge and the surface = 4.1cm
F ∝1/r²
Force on the charge is inversely proportional the square of distance between the charge and the surface.
Fr² = constant
F₁r₁² = F₂r₂²
F₂ = F₁r₁²/r₂²
If the charge is then moved 2.00 cm farther away from the surface;
The new distance becomes 4.10 cm + 2.00 cm = 6.1 cm
Therefore, r₂ = 6.1 cm, r₁ = 4.1 cm, F₁ =321 N
F₂ = (321 X4.1²)/(6.1²)
F₂ = 145.02N
Therefore, The new force on the test charge is 145.02N
Answer: adult males generally require 2,000-3000 calories per day, and adult females need 1,600-2,400.
There are two torques here, caused by the force on each end.
Torque = (force) x (distance from the pivot)
Left end: Torque = (300N) x (1m) = 300 N-m counterclockwise
Right end: Torques = (200 N) x (6m) = 1200 N-m clockwise
The net torque is (1200 - 300) = 900 N-m clockwise .
