The strength of the electric field on the point charge at this distance will be 4000 V/m.
<h3>What is the strength of the electric field?</h3>
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;
Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
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You’re answer is 1.
Once you drill something and put a hole in it that whole cannot be undone making it a chemical reaction.
Answer:
A 2 d vector model
The acceleration function is -9.8 m/s2 which is gravity
Initial velocity on the Y axis is 0, on the X axis is 12 m/s
Inital position is 20 mts above the ground.
It takes the water 1.01 seconds to reach the other building.
THe distace from one building to the other is 12.11 meters.
Explanation:
In order to solve this you just need to carefully read the problem and the data you are given, and use the formula for height in free fall:
So first the data, we know that the water is coming out at a height of 20 meters since the building is 19 meters tall and the fireman is holding the firehose 1 meter above it, and the water is hitting the second building at a height of 15 meters, that means that the water is travelin -5meters.
Gravity as it doesn´t say otherwise would be 9.8m/s2 since that is gravity on earth, and water is leaving the firehose at 12m/s horizontally.
We can calculate the time by using the height formula fro free fall:
So it takes 1.009 seconds for the water to frop from 20 to 15 meters, as the horizontal velocity remains the same we just multiply it by the time and we get the horizontal distance between the two buildings and that would be:
12.11 meters.
<span>
the horizontal velocity would be equal to
Vh = sin (40) /60
= 0.74 * 60
= 44
</span>
the Vertical velocity would be equal to
<span>Vv = cos(40) * 60
=40</span>
To solve this problem we will apply the concept related to the electric field. The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,
Here,
k = Coulomb's constant
V = Voltage
r = Distance
Replacing we have
Therefore the magnitude of the electric field is 
