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Agata [3.3K]
3 years ago
11

A 1250-kg car moves at 20.0 m/s. How much work must be done on the car to increase its speed to 30.0 m/s.

Physics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

312,497.5Joules

Explanation:

Work done = force × distance

W = FS

Get the force

F = ma

F = 1250×9.8

F = 12250N

Get the distances using the equation of motion

v² = u² +2gS

30² =20²+2(9.8)S

900 =400+19.6S

900-400 =19.6S

500 = 19.6S

S = 500/19.6

S = 25.51m

Get the work done

Work done = 12250×25.51

Workdone = 312,497.5Joules

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Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An
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Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.

Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.

<h3>What is the relation between the distance in parsecs and the parallax?</h3>
  • Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
  • Then, the equation connecting parallax and the distance in parsec can be written as,

                                     d=\frac{1}{P}

  • We can say that,

                                    dP=constant.\\thus,\\d_1P_1=d_2P_2

<h3>How to solve the problem?</h3>
  • We have given that,

                                     d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?

  • Thus, we can find the distance in parsecs as,

                                     d_2=\frac{d_1P_1}{P_2} =23.46 parsecs

Thus, we can conclude that, the distance in parsecs will be, 23.46.

Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776

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_____________ and ____________ can fly in the stratosphere.<br><br> Fill in blanks
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In what form is carbon found in the atmosphere
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Carbon dioxide or CO2 because when we breathe out thats what we release, and CO2 cant re-enter our body. Thats why people evantually run out of air in tight spaces, Because they turn all the air into CO2
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Find a model for simple harmonic motion that has an initial displacement (t=0) of 0 inches, an amplitude of 5 inches, and a freq
Svetach [21]

Answer:

The equation of simple harmonic motion is y=5\sin{(8\pi t)}

Explanation:

Given that,

Amplitude = 5 inches

Frequency f= \dfrac{4}{3}

As per the question initial displacement is zero at t = 0 for sine curve.

The displacement is zero so the phase difference will be zero.

We know that,

The general equation of simple harmonic motion

y=A\sin(\omega t+\phi)

Where, A = amplitude

\omega = angular frequency

\phi = phase shift

We need to calculate the time period

Using formula of frequency

f=\dfrac{1}{T}

T=\dfrac{1}{f}

Put the value into the formula

T=\dfrac{1}{\dfrac{4}{3}}

T=\dfrac{3}{4}

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\dfrac{2\pi}{T}

\omega=\dfrac{2\pi\times4}{3}

Put the value into the general equation

y=5\sin{(8\pi t)}

Hence, The equation of simple harmonic motion is y=5\sin{(8\pi t)}

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A large truck and a small car have a head-on collision. Which scenario is true?
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B. is the answer dude
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