The mass, in grams, of 2.90 x 10^-3 moles of Ammonium phosphate is 0.432 g.
<h2>Further Explanation:
</h2><h3>Moles, Atomic mass and Molar mass
</h3>
- 1 mole of a pure substance contains a mass that is equal to the relative atomic mass or molecular mass of the substance.
- Therefore; molar mass is given as grams per mole of a substance
- Molar mass of any element is equal to the atomic mass of that element in the unit of grams.
Molar mass = mass of a substance/ Number of moles
g/mol = g /mole
- M = m/n; where M is the molar mass, m is the mass and n is the number of moles
- From this relationship we can therefore, calculate mass by multiplying the number of moles by molar mass of a substance.
That is; Mass = moles x molar mass
<h3>
In this case;
</h3>
We need to calculate the mass of 2.90 x 10^-3 moles of Ammonium phosphate
<h3>Step 1: Molar mass of Ammonium phosphate </h3>
Molar mass of (NH4)3PO4 is given by;
= 3 x 14.0067 + 12 x 1.00794 + 30.973762 + 4 x 15.999
= 149.0851 g/mol (NH4)3PO4
<h3>
Step 2: Mass of 2.90 x 10^-3 moles of Ammonium phosphate
</h3>
1 mole of (NH4)3PO4 contains a mass of 149.0851 g
But;
Mass = Molar mass x Number of moles
= 149.0851 g/mol x 2.90 x 10^-3
= 0.432 g
Therefore; 2.90 x 10^-3 moles of Ammonium phosphate contains a mass of <u>0.432 g</u>
Keywords: Molar mass, moles
<h3>Learn more about:
</h3>
Level: High school
Subject: Chemistry
Topic: Moles
Sub-topic: Molar mass