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wlad13 [49]
3 years ago
8

Who’s has bigger cross sectional area capillaries or aorta?

Physics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

Even though the cross-sectional area of each capillary is extremely small compared to that of the large aorta, the total cross-sectional area of all the capillaries added together is about 1,300 times greater than the cross-sectional area of the aorta because there are so many capillaries

Explanation:

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A plane traveling north at 100.0 km/h through the air gets caught in a 40.0 km/h crosswind blowing west. This turbulence caused
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Answer:

The velocity \vec{v}_{c/g} of the cart with respect to the ground is

\vec{v}_{c/g}=-40\hat{x}+80\hat{y}\, km/h

if we consider North the positive y-direction and East the positive x-direction.

Explanation:

We have for relative motion the following expression:

\vec{v}_{c/g}=\vec{v}_{c/p}+\vec{v}_{p/g}

Where \vec{v}_{c/g} is the velocity of the cart with respect to the ground, \vec{v}_{c/p} is the velocity of the cart with respect to the plane and \vec{v}_{p/g} is the velocity of the plane with respect to the ground.

We find that:

\vec{v}_{c/p}=-20\hat{y}

\vec{v}_{p/g}=-40\hat{x}+100\hat{y}

Thus:

\vec{v}_{c/g}=-20\hat{y}-40\hat{x}+100\hat{y}=-40\hat{x}+80\hat{y} \, km/h

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3 years ago
What is the force exerted by a solid surface that opposes gravity?
jonny [76]

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3 years ago
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Answer the following. (a) What is the surface temperature of Betelgeuse, a red giant star in the constellation of Orion, which r
bagirrra123 [75]

Answer:

(a) T = 2987.6 k

(b) T = 19986.2 k

Explanation:

The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{\lambda_{max}}

where,

T = Radiated surface temperature

\lambda_{max} = peak wavelength

(a)

here,

\lambda_{max} = 970 nm = 9.7 x 10⁻⁷ m

Therefore,

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}

<u>T = 2987.6 k</u>

(b)

here,

\lambda_{max} = 145 nm = 1.45 x 10⁻⁷ m

Therefore,

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}

<u>T = 19986.2 k</u>

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