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Julli [10]
3 years ago
9

PLEASE HELP!!!! Scientists launch a rocket, and they monitor its acceleration and the force exerted by its engines. As the rocke

t gets higher, the monitors show that the acceleration of the rocket is increasing but the force exerted stays the same. How do Newton’s laws explain why the scientists could expect this to happen?
The total force stays the same, but the action force is increasing as the reaction decreases.
The mass of the rocket decreases as fuel is burned, so the acceleration increases.
The inertia of the rocket increases, which reduces the force needed to change its speed.
The reaction force is increasing as fuel is burned, which causes a greater acceleration.
Physics
2 answers:
kobusy [5.1K]3 years ago
5 0

i just took the test on edg enuity it was B.The mass of the rocket decreases as fuel is burned, so the acceleration increases.


DENIUS [597]3 years ago
4 0

Answer:

The mass of the rocket decreases as fuel is burned, so the acceleration increases.

Explanation:

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A force F with arrow applied to an object of mass m1 produces an acceleration of 3.10 m/s2. The same force applied to a second o
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Answer:

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(b)  the acceleration of the combined masses is 1.139 m/s²

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Given;

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The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

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(a) the value of the ratio m₁/m₂

since the applied force is same in both cases,  M₁a₁ = M₂a₂

\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

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a = \frac{F}{M} \\\\a =  \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}

But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} =  \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2

Therefore, the acceleration of the combined masses is 1.139 m/s²

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