Answer:
Explanation:
When 2 gms of steam condenses to water at 100 degree latent heat of vaporization is releases which is calculated as follows
Heat released = mass x latent heat of vaporization
= 2 x 2260 = 4520 J
When 2 gms of water at 100 degree is cooled to ice water at zero degree heat is releases which is calculated as follows
Heat released = mass x specific heat x( 100-0)
= 2 x 4.2 x 100 = 840 J
When 2 gms of water at zero degree condenses to ice at zero degree latent heat of fusion is releases which is calculated as follows
Heat released = mass x latent heat of fusion
= 2 x 334 = 668 J
When 2 grams of steam at 100 degrees Celsius turns to ice at 0 degrees Celsius heat released will be sum of all the heat released as mentioned above ie
4520 + 840 +668 = 6028 J
Answer:
<em>C. planetary accretion</em>
Explanation:
<em>Astronomers think planets formed from interstellar dust gases that clumped together in a process called </em><u><em>planetary accretion</em></u><em>.</em>
Given Information:
Current = I = 61 A
Magnetic field = B = 1.30x10⁻⁴
Required Information:
Radius of wire = r = ?
Answer:
r = 0.093 meters
Step-by-step explanation:
Biot-Savart Law is given by
B = μ₀I/2πr
Where μ₀ is the permeability of free space and it is basically a measure of resistance in the formation of magnetic field.
I is the current flowing through the wire and B is the magnitude of the magnetic field produced.
Re-arranging the above equation to find out the radius of the loop
r = μ₀I/2πB
r = 4πx10⁻⁷*61/2π*1.30x10⁻⁴
r = 0.093 m
Hence, the radius of the loop wire is 0.093 meters.