Answer:
Explanation:
Given that,
The mass of a toy, m = 0.62 kg
Force with which a child pull the toy = 16.3 N
The force with which the toy pulled in the opposite direction = -15.8 N
We need to find the acceleration of the toy. Let F be the net force acting on the toy. It is equal to :
F = 16.3 N - (-15.8 N)
= 32.1 N
Let a be the acceleration of the toy. Using Newton' second law of motion to find it.
F = ma
So, the acceleration of the toy is .
Answer:
I₁ =1250 kg.m²
Explanation:
Given that
Angular speed of Merry ,ω₁= 0.2 rad/s
Angular speed of technician ,ω₂= 0.04 rad/s
Moment of the inertia of the technician ,I₂= 5000 kg.m²
Lets assume that
Moment of the inertia of merry with respected to the ground=I₁
There is no any external torque ,that is why angular momentum of the system will be conserve.
Now by conserving angular momentum
I₁ ω₁=(I₁+I₂)ω₂
I₁ x 0.2 = (I₁ +5000 ) x 0.04
I₁ (0.2-0.04) = 5000 x 0.04
I₁ =1250 kg.m²