Answer:
1s2 2s2 2p6 3s2 3p6
Explanation:
Calcium is the 20th element. It has 20 electrons in it's neutral state. The electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6 4s2
However in the compound; calcium chloride, it does not exist in it's neutral state.
CaCl2 --> Ca2+ + Cl-
In Ca2+ state, it has lost two electrons, The total number of electrons becomes; 20 - 2 = 18 electrons.
The electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6
It’s 5% because without the 5% you wouldn’t make it to 100 equally
Answer:
a) Base Peak
b) Base Peak
c) Molecular Ion
d) Base Peak and Radical Cation
e) The Parent Ion, Molecular Ion, the Radical Cation and the Base Peak
Explanation:
a) The Base Peak is assigned a relative intensity of 100.
b) The Base Peak is the most intense peak in the mass spectrum.
c) The Molecular Ion Peak represents the original molecule that has only lost an electron.
d) Base Peak and Radical Cation could be/represent a smaller, charged fragment of the original molecule.
e) The Parent Ion, the Molecular Ion, the Radical Cation/ the Base Peak is/represents a positively charged species.
Answer:
0.010g of C-14 would be later after 50,000 years
Explanation:
The kinetics of radioactive decay follows the equation:
Ln (N / N₀) = -kt
<em>Where N could be taken as mass after time t, </em>
<em>N₀ initial mass = 4.30g;</em>
k is rate constant = ln 2 / t(1/2)
<em>= ln 2 / 5730years = 1.2097x10⁻⁴ years ⁻¹</em>
<em />
Replacing:
Ln (N / 4.30g) = -1.2097x10⁻⁴ years ⁻¹ * 50000 years
N / 4.30 = 2.36x10⁻³
N =
<h3>0.010g of C-14 would be later after 50,000 years</h3>
Answer: The ground-state electronic configuration of
1) ![Ru^{2+}=[Kr]4d^6](https://tex.z-dn.net/?f=Ru%5E%7B2%2B%7D%3D%5BKr%5D4d%5E6)
2) ![W^{3+]=4f^{14}5d^3](https://tex.z-dn.net/?f=W%5E%7B3%2B%5D%3D4f%5E%7B14%7D5d%5E3)
Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.
Atomic number of the element = Number of electrons.
Atomic number = 44
Number of electrons = 44
Electronic configuration of Ru-element = ![[Kr]4d^75s^1](https://tex.z-dn.net/?f=%5BKr%5D4d%5E75s%5E1)
To form 
, 2 electrons are released from the neutral Ru-element.
So, the electronic configuration of
Atomic number = 74
Number of electrons = 74
Electronic configuration of W-element = ![[Xe]4f^{14}5d^46s^2](https://tex.z-dn.net/?f=%5BXe%5D4f%5E%7B14%7D5d%5E46s%5E2)
To form 
, 3 electrons are released from the neutral W-element.
So, the electronic configuration of ![W^{3+}=[Xe]4f^{14}5d^3](https://tex.z-dn.net/?f=W%5E%7B3%2B%7D%3D%5BXe%5D4f%5E%7B14%7D5d%5E3)
