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KIM [24]
2 years ago
15

4. (10 Points) Write a single replacement reaction where one of the reactants is

Chemistry
1 answer:
lesya [120]2 years ago
3 0

Answer:

For each balanced reaction, indicate the total number of atoms in the table below. Reaction. Total Number of Atoms. Reactant Side 1 Product Side. (Left).

Explanation:

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How many grams Kl are needed to prepare 100.mL of 0.55M solution?​
Makovka662 [10]

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

7 0
2 years ago
Which is a gas at room temperature?
dalvyx [7]

Answer:

Several of the nonmetals are gases in their elemental form. Elemental hydrogen (H, element 1), nitrogen (N, element 7), oxygen (O, element 8), fluorine (F, element 9), and chlorine (Cl, element 17) are all gases at room temperature, and are found as diatomic molecules (H2, N2, O2, F2, Cl2).

Explanation:

8 0
3 years ago
Read 2 more answers
The protons of an atom are
Triss [41]
B protons are positive atoms and are inside the nucleus
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3 years ago
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Choose the answer that best explains why α–pyrone reacts with br2 to yield a substitution product (like benzene does), rather th
meriva

As can be seen in the attached image, α-pyrone has a highly electrophilic carbon atom, since it is attached to two oxygen atoms that are electronegative and subtract electrical charge from the carbon, leaving it with a <u>positive partial charge</u>. By virtue of the above, <u>the bromine atoms, which have an important electron density that makes them good nucleophiles, will be attracted to the aforementioned carbon due to their positive charge</u>, thus favoring the substitution product to a greater extent than that of addition.

7 0
3 years ago
Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un
maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0
3 years ago
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