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2 years ago

Water enters a shower head through a pipe of radius 0.0112 m at 3.25 m/s. What is it’s volume flow rate? (Unit= m^3/s)

Physics

2 answers:

kenny6666 [7]2 years ago

7 0

Answer:

$1.28 \times 10 ^{-3} m^3/s$

Explanation:

Given that the radius of the pipe, r =0.0112 m

So, the area of the cross-section, $a= \pi (0.0112)^2 = 3.941\times 10^{-4} m^2$

Speed of water in the pipe, v=3.25 m/s

Volume flow rate = $av= 3.941\times 10^{-4} \times 3.25 = 1.28\times 10 ^{-3} m^3/s$

Hence, the volume flow rate is $1.28 \times 10 ^{-3} m^3/s$

tangare [24]2 years ago

4 0

Answer:

For Acellus the answer is 0.00128

Explanation:

Trust me

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