Answer:
3.0×10⁻¹³ M
Explanation:
The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.
<h3>Equation</h3>
The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.
Ksp = [Al₃⁺³]×[OH⁻]³
<h3>Solving for [Al₃⁺³]</h3>
The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.
This means the solubility product equation is ...
Ksp = x(10⁻⁷ +3x)³
For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...
3.0×10⁻³⁴ = x(10⁻⁷)³
Then x = [Al₃⁺³] will be ...
![[\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}](https://tex.z-dn.net/?f=%5B%5Ctext%7BAl%7D_3%5E%7B%5C%2C%2B3%7D%5D%3D%5Cdfrac%7B3.0%5Ctimes10%5E%7B-34%7D%7D%7B10%5E%7B-21%7D%7D%5Capprox%20%5Cboxed%7B3.0%5Ctimes10%5E%7B-13%7D%5Cqquad%5Ctext%7Bmoles%20per%20liter%7D%7D)
We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.
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<em>Additional comment</em>
The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.
The equation for the overall reaction obtained by adding these equations is; 2NO₂(g) ⇒ N₂O₄(g)
<h3>How to simplify chemical equations?</h3>
We are given equations;
2NO₂(g) ----> 2NO(g) + O₂(g) ---(1)
2NO(g) -----> N₂(g) + O₂(g) -----(2)
N₂(g) + 2O₂(g) ----> N₂O₄(g) -----(3)
Add eq 1 and eq 2 to get;
2NO₂(g) + 2NO(g) ⇒ 2NO(g) + O₂(g) + N₂(g) + O₂(g)
2NO will cancel out to get;
2NO₂(g) ⇒ N₂(g) + 2O₂(g) -----(4)
Add eq 3 to eq 4 to get;
N₂(g) + 2O₂(g) + 2NO₂(g) ⇒ N₂O₄(g) + N₂(g) + 2O₂(g)
This will reduce to;
2NO₂(g) ⇒ N₂O₄(g)
The correct question is;
Consider the chemical equations shown here.
2NO₂(g) ----> 2NO(g) + O₂(g)
2NO(g) -----> N₂(g) + O₂(g)
N₂(g) + 2O(g) ----> N₂O₄(g)
What is the equation for the overall reaction obtained by adding these equations?
Read more about chemical equations at; brainly.com/question/19837884
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<span>Filtration, if its a precipitate that means its insoluble. </span>
The answer is without access to energy
The better era tbh.......