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IgorC [24]
3 years ago
15

Additive area

Mathematics
1 answer:
igomit [66]3 years ago
8 0

B, 27 ft²

2*3 + 7*3 = 27

but for this one you could just actually count the tiles

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Help ASAP!!!<br> Please and thank you
katovenus [111]
The area of the triangle should be 20. Try that out
5 0
3 years ago
Sheila works 8.5 hours per day on Monday,Wednesday and Friday, and 6 hours per day on Tuesday and Thursday.she earns $356.25 per
Artist 52 [7]

Answer:

9.50/ per hour

Step-by-step explanation:

adding the 8.5 x 3 (M/W/F)

plus the 6 x 2 (T/TH)

= 37.5 hours

356.75 divided by 37.5 = 9.5

Hope this helps

6 0
3 years ago
Y is directly proportional to square root of x<br> If y=56 when x=49 find,<br> y when x=81
STALIN [3.7K]

\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72

7 0
2 years ago
Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
The length of sides of triangular fields are 10m, 24m and 26m. A farmer grows flowers in this field. If 5kg flowers can be obtai
Ostrovityanka [42]

Answer:

Area: 120m²

Flowers: 600kg

Step-by-step explanation:

we can use Heron's formula to solve for the area.

Heron's formula:

Area of triangle = \sqrt{ s(s-a)(s-b)(s-c)}

s = 1/2 (a+b+c)

s = 1/2 (10 +24+26)

s = 30

Area of triangle

=\sqrt{30(30-10)(30-24)(30-26)} \\=120m^{2}

Since every 1 m² of area can grow 5kg of flowers,

the yield of flowers will be:

120 x 5

=600kg

7 0
3 years ago
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