X=10 and y=5 so it's the first option
The foci need to be equal distances from the center of the eclipse.
See the attached picture. I marked off all the points that were given as choice and from this you can see that that (-5,-4) and (-5,2) are both 3 units away from the center.
The answer is: (-5,-4) and (-5,2)
Answer:
Step-by-step explanation:
The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate. Also called "Abscissa"
Answer:
A: 779 cm²
B: 1837 cm²
Step-by-step explanation:
For both problems, use the formula for surface area of a cylinder:
SA = 2πr² + 2πrh
2πr² is the two bases.
2πrh is the curved surface.
<u>PROBLEM A</u>
"the cylinder is 60 cm long" is h = 60.
If given diameter, you can find "r" by dividing it by 2. d = 2r
Given d = 4, then r = 2.
SA = 2πr² + 2πrh
SA = 2π2² + 2π2(60)
SA = 8π + 240π Add
SA = 248π Exact answer
SA ≈ 779.114978 Answer on calculator
SA ≈ 779 Rounded answer
Remember to include the units.
The surface area is about 779 cm².
<u>PROBLEM B</u>
"80 cm long" h = 80.
"circumference of 22 cm". C = 22. Remember C = 2πr. Find "r".
C = 2πr
22 = 2πr
11 = πr
r ≈ 11/π
SA = 2πr² + 2πrh
SA = 2π(11/π)² + 22(80) Substitute 2πr with the circumference.
SA ≈ 1837.030992 Answer on calculator
SA ≈ 1837 Rounded answer
Remember to include the units.
The surface area is about 1837 cm².
Answer:
46/ 67
Step-by-step explanation:
The numbers of students irrespective of grades is;
The sum of the last roll of numbers:
10+24+ 33+ 67 = 134
The number of males irrespective of grades is the sum of the numbers in the male row ;
7 +20+ 14 +41= 82
The numbers of students with grade A is the first column at the last row and is 10;
Hence;
the probability that the student was male OR got an 'A' is
the probability that the student was male plus the probability that he/she got an 'A'.
The probability that it's a male is ;
Number of males/ total number of students
=82/134
The probability that he got an A is;
The number of students that got A/ the total number of students;
10/134
Hence
the probability that the student was male OR got an 'A' is;
82/ 134 + 10/134 = 92/134 = 46/ 67
