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Rashid [163]
2 years ago
10

What is the uncertainty of a 10ml pipet?​

Chemistry
1 answer:
EleoNora [17]2 years ago
3 0

Answer: the certain of a 10ml pipet is listed as, 10.00 0.02,

Explanation: those numbers are close to 4 significant figures as in (10ml) around the amount you're looking for. , hope that makes sense!

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Select the item(s) that are organs in either a plant or human
Nataly_w [17]
Plant: leaf tissue
Human: lungs
3 0
3 years ago
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4
forsale [732]
The molarity of H2SO4 is the number of moles in 1 L of solution.
The molarity is 2.0 mol/L
This means that there should be 2 moles in a 1 L solution to make up this molarity.
In this case we need to make up a 5 L solutions with that molarity. Then the amount of moles required are - 2 mol/L x 5 L = 10 mol
3 0
3 years ago
Read 2 more answers
Anita was using steel to make rusted sculptures. After building each sculpture, she caused the steel in the sculpture to rust by
alexandr1967 [171]

Answer:

The type of liquid in the tub (salt water or vinegar)

Explanation:

<em>The manipulated independent variable in Anita's experiment is </em><em>the type of liquid in the tub. </em>

The independent variable is the controlled or manipulated variable in the course of an experiment. It can also be referred to as the 'cause' variable which has the capacity to produce 'effects' on another variable - the dependent variable.

In this case, the type of liquid the tub is filled (salt water or vinegar) will hypothetically affect the rusting period of the steel. Hence, the dependent variable is the type of liquid the tub is filled while the dependent variable would be the time it takes for the steel to get rusted.

5 0
3 years ago
You have 1.6 x10 21 atoms of oxygen, what is the mass of that number of atoms
iren [92.7K]

Answer: 166.023×1023

Explanation:

Mass of 6.023×1023 atoms of oxygen = gram atomic mass of oxygen.

Mass of 6.023×1023 atoms of oxygen = 16g

∴ Mass of 1 atom of oxygen =166.023×1023

6 0
3 years ago
A chiral amine A having the R configuration undergoes Hofmann elimination to form an alkene B as the major product. B is oxidati
Free_Kalibri [48]

Answer:

The Structure of "B" is alkene.

Explanation:

The compound "A" having R- configuration  and undergoes Hofmann elimination to form an alkene.

The compound "B" on oxidatively cleaving with ozone followed by dimethyl sulfide forms CH_{2}=S and CH_{3}CH_{2}CH_{2}CHO

The structure of "A" and"B" is as follows.

3 0
3 years ago
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