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serious [3.7K]
2 years ago
8

What is fundamental unit?​

Physics
1 answer:
matrenka [14]2 years ago
6 0

Answer:

The fundamental units are the base units defined by International System of Units. These units are not derived from any other unit, therefore they are called fundamental units. The seven base units are: Meter (m) for Length. Second (s) for Time.

Explanation:

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With a 12 V battery, what is the voltage drop across each resistor?
anzhelika [568]
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In a series circuit, the voltage divides across the resistors in proportion to
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3 years ago
32. (FR) A mass moving at 25 m/s slides along a rough horizontal surface. The coefficient of friction is 0.30. (A) Use force and
scoray [572]

Answer:

A)s = 104.16 m

b)s= 104.16 m

Explanation:

Given that

u = 25 m/s

μ = 0.3

The friction force will act opposite to the direction of motion.

Fr= μ m g

Fr= -  m a

a=acceleration

μ m g = - m a

a= - μ g

a= - 0.3 x 10 m/s²          ( take g= 10 m/s²)

a= - 3  m/s²

The final speed of the mass is zero ,v= 0

We know that

v² = u² +2 a s

s=distance

0² = 25² - 2 x 3 x s

625 = 6 s

s = 104.16 m

By using energy conservation

Work done by all the forces =Change in the kinetic energy

- Fr.s=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

Negative sign because force act opposite to the displacement.

- \mu\ m\ g \ s=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

-\mu\ g \ s=\dfrac{1}{2}v^2-\dfrac{1}{2}u^2

-0.3\times 10\times \ s=\dfrac{1}{2}\times 0^2-\dfrac{1}{2}\times 25^2

- 3 x 2 x s = - 625

s= 104.16 m

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3 years ago
Which of the following has the most momentum?
IrinaK [193]

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3 years ago
The first four steps in the formation of the sun are listed below.
Airida [17]
(B)Option b is your answer..........
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3 years ago
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Class II levers like ankles and wheelbarrows are useful because they provide mechanical advantage, by amplifying the input force
marusya05 [52]

Answer:

The solution and the explanation are in the Explanation section.

Explanation:

According to the diagram that is in the attached image, the EFFORT force at point A and the load is at O point. The torque due to weight is:

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The torque due to effort at C point is:

TC = E * (b * cosθ)

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Tnet = 0

W * (a * cosθ) - E * (b * cosθ) = 0

E=W\frac{a}{b}

From the figure, you can observe that a/b < 1, thus E < W

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